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BINOMNI KOEFICIJENTI

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<strong>BINOMNI</strong> TEOREM<br />

Nekoliko jednostavnih posljedica binomnog teorema:<br />

Teorem 8<br />

(i)<br />

(ii)<br />

(iii)<br />

( ) ( ) ( ) ( ) ( )<br />

n n n n<br />

n∑ n<br />

+ + + . . . + = = 2 n<br />

0 1 2 n k<br />

k=0<br />

( ) ( ) ( ) ( ) ( )<br />

n n n<br />

− + − . . . + (−1) n n<br />

n∑<br />

= (−1) k n<br />

= 0<br />

0 1 2<br />

n<br />

k<br />

k=0<br />

( ) ( ) ( ) ( ) ( ) ( )<br />

n n n n n n<br />

+ + + . . . = + + + . . . = 2 n−1 .<br />

0 2 4 1 3 5<br />

Dokaz:<br />

(i) kombinatorno već dokazan, a može se dokazati i tako da koristimo binomni teorem:<br />

stavimo x = y = 1 u binomnoj formuli.<br />

(ii) x = 1, y = −1 u binomnoj formuli<br />

(iii) parnih podskupova ima jednako mnogo kao i neparnih. Kako je ukupno 2 n<br />

1<br />

podskupova, tvrdnja slijedi iz (i):<br />

2 2n = 2 n−1 .<br />

() 21. studenog 2011. 18 / 27

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