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MATEMATIKA 1 Senka Banic PREDAVANJA (grupa G1): utorak i ...

MATEMATIKA 1 Senka Banic PREDAVANJA (grupa G1): utorak i ...

MATEMATIKA 1 Senka Banic PREDAVANJA (grupa G1): utorak i ...

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12Ako razmatramo drugo suenje polazne funkcijeh = f h 1;0]: h 1; 0] ! [0; +1i ; h (x) = x 2 ;koje je tako ¯der bijekcija, inverzna funkcija tog suenja jeh 1 : [0; +1i ! h 1; 0] ; h 1 (y) = y 1 2 =p y:Zaista, prema izrazima (1) i (2) imamo:h h 1 (y) = h h 1 (y) = hy 1 2=y 1 2 2=y 1 2 2= y; 8y 2 [0; +1i ih 1 h (x) = h 1 (h (x)) = h 1 x 2 = x 2 12= jxj = x; 8x 2 h 1; 0]pa su h h 1i h 1 h odgovarajuće identitete, kako se i trailo.

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