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Practical Ship Hydrodynamics

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<strong>Ship</strong> manoeuvring 205<br />

The ship performs a pull-out manoeuvre and the following curve for P is<br />

recorded:<br />

0.020<br />

0.010<br />

0.007<br />

•<br />

y (rad/s)<br />

10 20<br />

(a) Determine the constants T and ˛!<br />

(b) Sketch a corresponding curve of P for the case that at t D 0, P D<br />

0.002 rad/s instead of P D 0.02 rad/s.<br />

5. Determine the rudder lift at 10° rudder angle for the semi-balanced rudder<br />

behind a propeller and hull of a ferry as shown below. The ship speed is<br />

30 kn, the propeller thrust 4000 kN. The wake fraction is w D 0.25. Correct<br />

the rudder lift for the propeller loading according to Söding (1998a, b).<br />

Following Goodrich and Mooland (1979) we may assume that at 10°<br />

rudder angle a semi-balanced rudder as the one depicted may have 79.2%<br />

of the lift of a ‘normal’ rudder.<br />

Dimensions are to be taken from the sketch (see p. 206).<br />

6. The container ship in Tables 5.1 and 5.2 sails in a turning circle with rudder<br />

in the centre position using just its bow thruster at maximum power. The<br />

bow thruster is located 4 m aft of the forward perpendicular. The power of<br />

the thruster is 4000 kW. The pipe diameter is 2.5 m. The ship speed is 5 kn.<br />

The efficiency of the bow thruster is D 0.8.<br />

Compute the radius of the turning circle R assuming linear correlation<br />

between hull forces and motions. The radius of the turning circle follows<br />

from the relation U D r Ð R, wherer is the yaw rate.<br />

Forward speed changes the thrust of a bow thruster T from the value at<br />

zero speed T0:<br />

T/T 0<br />

−5 5 10<br />

1<br />

U (kn)<br />

t (s)

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