EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
EC2 – worked examples 7-18<br />
EXAMPLE 7.6 Verification of limit state of deformation<br />
Evaluate the vertical displacement in the mid-spam of the beam in Figure 7.11 with constant<br />
transversal section represented in Figure 7.12<br />
Fig. 7.11. deflected beam, deformation limit state.<br />
Assume the following values for the main parameters<br />
f ck=30MPa; g+q=40kN/m; g=2q; l=10m; A s=3164mm 2 (7φ24) ;<br />
Table of Content<br />
Fig. 7.12. Transversal section.<br />
and solve the problem firstly in a cumulative way, stating αe = Es/Ec=15. Referring to the stage I, as indicated in Figure 7.13,<br />
A = 700⋅ 500 + 15⋅ 3164 = 397460mm<br />
* 2<br />
( 700⋅500⋅ 350 + 15⋅3164 ⋅650)<br />
*<br />
yG =<br />
397460<br />
= 385.8mm<br />
I<br />
500 ⋅700<br />
12<br />
500 700 35.8 15 3164 650 385.8 18.05 10 mm<br />
9<br />
* 18.05⋅10 7 3<br />
Wi = = 5.745⋅10 mm<br />
700 − 385,8<br />
3<br />
* 2 2<br />
9 4<br />
I = + ⋅ ⋅ + ⋅ ⋅( − ) = ⋅<br />
From Table [3.2-EC2] we get<br />
ctm<br />
and then the cracking moment results<br />
* 7 −6<br />
cr ctm i<br />
2 3<br />
f = 0.30⋅ 30 = 2.9MPa<br />
M = f W = 2.9⋅5.745⋅10 ⋅ 10 = 166.6kNm<br />
Considering the whole applied load then<br />
M 500<br />
max λ= = =<br />
Mcr 166.6<br />
3<br />
2<br />
M 40 10<br />
max = ⋅<br />
8<br />
= 500kNm<br />
Fig. 7.13. Section at stage I.<br />
In the stage II, as reported in Figure 7.13,