01.03.2013 Views

EUROCODE 2 WORKED EXAMPLES - Federbeton

EUROCODE 2 WORKED EXAMPLES - Federbeton

EUROCODE 2 WORKED EXAMPLES - Federbeton

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

EC2 – worked examples 7-18<br />

EXAMPLE 7.6 Verification of limit state of deformation<br />

Evaluate the vertical displacement in the mid-spam of the beam in Figure 7.11 with constant<br />

transversal section represented in Figure 7.12<br />

Fig. 7.11. deflected beam, deformation limit state.<br />

Assume the following values for the main parameters<br />

f ck=30MPa; g+q=40kN/m; g=2q; l=10m; A s=3164mm 2 (7φ24) ;<br />

Table of Content<br />

Fig. 7.12. Transversal section.<br />

and solve the problem firstly in a cumulative way, stating αe = Es/Ec=15. Referring to the stage I, as indicated in Figure 7.13,<br />

A = 700⋅ 500 + 15⋅ 3164 = 397460mm<br />

* 2<br />

( 700⋅500⋅ 350 + 15⋅3164 ⋅650)<br />

*<br />

yG =<br />

397460<br />

= 385.8mm<br />

I<br />

500 ⋅700<br />

12<br />

500 700 35.8 15 3164 650 385.8 18.05 10 mm<br />

9<br />

* 18.05⋅10 7 3<br />

Wi = = 5.745⋅10 mm<br />

700 − 385,8<br />

3<br />

* 2 2<br />

9 4<br />

I = + ⋅ ⋅ + ⋅ ⋅( − ) = ⋅<br />

From Table [3.2-EC2] we get<br />

ctm<br />

and then the cracking moment results<br />

* 7 −6<br />

cr ctm i<br />

2 3<br />

f = 0.30⋅ 30 = 2.9MPa<br />

M = f W = 2.9⋅5.745⋅10 ⋅ 10 = 166.6kNm<br />

Considering the whole applied load then<br />

M 500<br />

max λ= = =<br />

Mcr 166.6<br />

3<br />

2<br />

M 40 10<br />

max = ⋅<br />

8<br />

= 500kNm<br />

Fig. 7.13. Section at stage I.<br />

In the stage II, as reported in Figure 7.13,

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!