EUROCODE 2 WORKED EXAMPLES - Federbeton

EC2 – worked examples 6-8
• VEd = 900 kN; fck = 60 MPa ; fcd = 34 MPa ; ν = 0.532
1 2VEd
1 2 ⋅900000
θ= arcsin = arcsin = 23.74
2 ( α νf )b z 2 (1⋅0.532⋅34) ⋅200⋅675 Table of Content
cw cd w
Asw VEd 900000
2
Then with it results = = = 1.35 mm / mm
s z⋅f⋅cotθ 675⋅435⋅2.27 which is satisfied with 2-leg stirrups φ12/160 mm.
ywd
o
hence cotθ = 2.27
The tensile force in the tensioned longitudinal reinforcement necessary for bending
must be increased by ΔFtd = 0.5 VEd cot θ = 0.5·900000·2.27 = 1021 kN
• VEd = 1200 kN; fck = 90 MPa ; fcd = 51 MPa ; ν = 0.512
1 2VEd
1 2 ⋅1200000
θ= arcsin = arcsin = 21.45
2 ( α νf )b z 2 0.512⋅51⋅200⋅675 cw cd w
As θ is smaller than 21.8 o , cotθ = 2.50
Asw VEd 1200000
2
Hence = = = 1.63 mm / mm
s z⋅f⋅cotθ 675⋅435⋅2.50 ywd
which is satisfied with 2-leg stirrups φ12/130 mm.
The tensile force in the tensioned longitudinal reinforcement necessary for bending
must be increased by ΔFtd = 0.5 VEd cot θ = 0.5·1200000·2.50 = 1500 kN
o