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EUROCODE 2 WORKED EXAMPLES - Federbeton

EUROCODE 2 WORKED EXAMPLES - Federbeton

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EC2 – Worked examples 4-6<br />

We have:<br />

c = 1,5 · 12,5 = 18,8 mm .<br />

min,b<br />

We obtain from table 4.5N - EC2:<br />

c = 35 mm .<br />

min,dur<br />

Moreover:<br />

Δc dur, γ = 0 ;<br />

Δc dur,st = 0 ;<br />

Δc = 0 .<br />

dur,add<br />

From relation (3.2):<br />

c = max (18,8; 35 + 0 – 0 – 0; 10 mm) = 35 mm .<br />

min<br />

Moreover:<br />

Δc = 5 mm .<br />

dev<br />

From relation (3.1):<br />

c = 35 + 5 = 40 mm .<br />

nom<br />

The first strand’s axis is placed at 50mm from the lower end of the ribbing of the TT<br />

element. The concrete cover for the lower strands of the TT element (one for each ribbing)<br />

is therefore equal to 43mm.<br />

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