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EUROCODE 2 WORKED EXAMPLES - Federbeton

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EC2 – worked examples 11-3<br />

EXAMPLE 11.2 [EC2 Clause 11.3.1 – 11.3.5 – 11.3.6 – 11.4 – 11.6]<br />

The maximum moment that the reinforced concrete section of given dimensions, made of<br />

type 1 lightweight concrete, described in the previous example, is able to withstand when<br />

the reinforcement steel achieves the design elastic limit. The dimensions of the section are:<br />

b=30 cm, h=50cm and d=47cm.<br />

The section in question is shown in Fig. 11.1 together with the strain diagram related to the<br />

failure mode recalled, which implies the simultaneous achievement of maximum<br />

contraction side concrete and of the strain corresponding to the design yield stress of the<br />

tensioned reinforcement steel.<br />

In case one chooses, like in the previous example, to use the bilinear diagram to calculate<br />

the compressive strength on concrete, the limits of strain by compression have values εlc3 =<br />

1,75‰ and εlcu3 = 3,5η1 = 2,98‰.<br />

The design strain corresponding to steel yielding, for fyk= 450 MPa, is εyd = fyd /(1,15 x Es)<br />

= 450/(1,15 x 200000) = 1,96‰. The distance of the neutral axis from the compressed<br />

upper edge is therefore x = 28,3 cm.<br />

Two areas can be distinguished in the compressed zone: the first one is comprised between<br />

the upper edge and the chord placed at the level where the contraction is εlc3 = 1,75‰. The<br />

compressive stress in it is constant and it is equal to flcd = 0,85 flck/γc = 19,8 MPa; the<br />

second remaining area is the one where compression on concrete linearly decreases from<br />

the value flcd to zero in correspondence of the neutral axis.<br />

The resultant of compression forces is placed at a distance of around 10,5 cm from the<br />

compressed end of the section and is equal to C = 1185 kN. For the condition of<br />

equilibrium the resultant of compressions C is equal to the resultant of tractions T, to<br />

which corresponds a steel section As equal to As = T/fyd = 3030 mm 2 . The arm of internal<br />

forces is h’ = d – 10,5 cm = 36,5 cm, from which the value of the moment resistance of the<br />

section can eventually be calculated as MRd = 1185 x 0,365 = 432,5 kNm.<br />

Fig.11.1 Deformation and tension diagram of r.c. section, build up with lightweight concrete<br />

(flck = 35 MPa, ρ = 1650 kg/m 3 ), for collapse condition in which maximum resisting bending moment is<br />

reached with reinforcement at elastic design limit.<br />

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