EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
EC2 – worked examples 11-3<br />
EXAMPLE 11.2 [EC2 Clause 11.3.1 – 11.3.5 – 11.3.6 – 11.4 – 11.6]<br />
The maximum moment that the reinforced concrete section of given dimensions, made of<br />
type 1 lightweight concrete, described in the previous example, is able to withstand when<br />
the reinforcement steel achieves the design elastic limit. The dimensions of the section are:<br />
b=30 cm, h=50cm and d=47cm.<br />
The section in question is shown in Fig. 11.1 together with the strain diagram related to the<br />
failure mode recalled, which implies the simultaneous achievement of maximum<br />
contraction side concrete and of the strain corresponding to the design yield stress of the<br />
tensioned reinforcement steel.<br />
In case one chooses, like in the previous example, to use the bilinear diagram to calculate<br />
the compressive strength on concrete, the limits of strain by compression have values εlc3 =<br />
1,75‰ and εlcu3 = 3,5η1 = 2,98‰.<br />
The design strain corresponding to steel yielding, for fyk= 450 MPa, is εyd = fyd /(1,15 x Es)<br />
= 450/(1,15 x 200000) = 1,96‰. The distance of the neutral axis from the compressed<br />
upper edge is therefore x = 28,3 cm.<br />
Two areas can be distinguished in the compressed zone: the first one is comprised between<br />
the upper edge and the chord placed at the level where the contraction is εlc3 = 1,75‰. The<br />
compressive stress in it is constant and it is equal to flcd = 0,85 flck/γc = 19,8 MPa; the<br />
second remaining area is the one where compression on concrete linearly decreases from<br />
the value flcd to zero in correspondence of the neutral axis.<br />
The resultant of compression forces is placed at a distance of around 10,5 cm from the<br />
compressed end of the section and is equal to C = 1185 kN. For the condition of<br />
equilibrium the resultant of compressions C is equal to the resultant of tractions T, to<br />
which corresponds a steel section As equal to As = T/fyd = 3030 mm 2 . The arm of internal<br />
forces is h’ = d – 10,5 cm = 36,5 cm, from which the value of the moment resistance of the<br />
section can eventually be calculated as MRd = 1185 x 0,365 = 432,5 kNm.<br />
Fig.11.1 Deformation and tension diagram of r.c. section, build up with lightweight concrete<br />
(flck = 35 MPa, ρ = 1650 kg/m 3 ), for collapse condition in which maximum resisting bending moment is<br />
reached with reinforcement at elastic design limit.<br />
Table of Content