EUROCODE 2 WORKED EXAMPLES - Federbeton

EC2 – worked examples 6-12
EXAMPLE 6.7 Shear – Torsion interaction diagrams [EC2 clause 6.3]
Table of Content
Fig. 6.3 Rectangular section subjected to shear and torsion
Example: full rectangular section b = 300 mm , h = 500 mm, z =400 mm (Fig. 6.3)
Materials:
fck = 30 MPa
fcd = 0.85·(30/1.5) = 17.0 MPa
⎛ 30 ⎞
ν= 0.7⋅⎜1− ⎟=
0.616 ; ν fcd = 10.5 MPa
⎝ 250 ⎠
fyk = 450 MPa ; fyd = 391 MPa
αcw = 1
Geometric elements
A= 150000 mm 2
u = 1600 mm
t = A/u = 94 mm
resistant hollow
section
Ak = (500 – 94) ⋅ (300-94) = 83636 mm 2
Assumption: θ = 26.56 o (cotθ = 2.0)
It results: VRd,max = αcw ⋅ bw⋅z⋅ν⋅fcd/ (cot θ+ tan θ) = 10.5⋅300⋅400/(2+0.5) = 504 kN
and for the taken z = 400 mm
TRd,max = 2⋅10.5⋅83636⋅94⋅0.4471⋅0.8945 = 66 kNm