EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
EUROCODE 2 WORKED EXAMPLES - Federbeton
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EC2 – Worked examples 4-2<br />
Moreover:<br />
Δc = 10 mm.<br />
dev<br />
We obtain from relation (3.1):<br />
c = c + Δc = 15 + 10 = 25 mm .<br />
nom min dev<br />
If we now calculate now the concrete cover for longitudinal reinforcement bars,<br />
we have:<br />
c = 20 mm.<br />
min,b<br />
We obtain from table 4.4N - EC2:<br />
c = 15 mm .<br />
min,dur<br />
Moreover:<br />
Δc dur, γ = 0 ;<br />
Δc dur,st = 0 ;<br />
Δc = 0 .<br />
dur,add<br />
From relation (3.2):<br />
c = max (20; 15 + 0 – 0 – 0; 10 mm) = 20 mm .<br />
min<br />
Moreover: Δc dev = 10 mm.<br />
We obtain from relation (3.1):<br />
c = 20 + 10 = 30 mm .<br />
nom<br />
The concrete cover for the stirrups is “dominant”. In this case, the concrete cover for<br />
longitudinal bars is increased to: 25 + 8 = 33 mm .<br />
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