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EUROCODE 2 WORKED EXAMPLES - Federbeton

EUROCODE 2 WORKED EXAMPLES - Federbeton

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EC2 – Worked examples 4-2<br />

Moreover:<br />

Δc = 10 mm.<br />

dev<br />

We obtain from relation (3.1):<br />

c = c + Δc = 15 + 10 = 25 mm .<br />

nom min dev<br />

If we now calculate now the concrete cover for longitudinal reinforcement bars,<br />

we have:<br />

c = 20 mm.<br />

min,b<br />

We obtain from table 4.4N - EC2:<br />

c = 15 mm .<br />

min,dur<br />

Moreover:<br />

Δc dur, γ = 0 ;<br />

Δc dur,st = 0 ;<br />

Δc = 0 .<br />

dur,add<br />

From relation (3.2):<br />

c = max (20; 15 + 0 – 0 – 0; 10 mm) = 20 mm .<br />

min<br />

Moreover: Δc dev = 10 mm.<br />

We obtain from relation (3.1):<br />

c = 20 + 10 = 30 mm .<br />

nom<br />

The concrete cover for the stirrups is “dominant”. In this case, the concrete cover for<br />

longitudinal bars is increased to: 25 + 8 = 33 mm .<br />

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