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EUROCODE 2 WORKED EXAMPLES - Federbeton

EUROCODE 2 WORKED EXAMPLES - Federbeton

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EC2 – worked examples 6-27<br />

node 1 equilibrium C’ 1 = 500 kN<br />

node 2 equilibrium<br />

C’2 = C’1 = 500 kN<br />

T'1 = 1<br />

2 ⋅ C' = 707 kN<br />

node 3 equilibrium<br />

C’3 = T’1 = 707 kN<br />

T’2 = (T’1 + C’3)·cos 45° = 1000 kN<br />

Tension rods<br />

for tension rod T’ 2 it is necessary to adopt a steel area not lower than:<br />

1000000<br />

2<br />

As1 ≥ = 2556 mm<br />

391.3<br />

6φ24 = 2712 mm 2 are adopted,<br />

a lower reinforcement area would be sufficient for tension rod T’ 1 but for question of bar<br />

anchoring the same reinforcement as in T’ 2 is adopted.<br />

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