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N=2 Supersymmetric Gauge Theories with Nonpolynomial Interactions

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3.2. Transformations and Bianchi Identities 39<br />

This finishes the solution to the consistency conditions (C.1–4) subject to the restriction<br />

(2.71) and F = 0. The complete set of coefficient functions reads<br />

A = B = 2<br />

¯Z − Z<br />

D = ¯ Z∂g<br />

¯Z − Z , E = ¯ Z ¯ ∂¯g<br />

¯Z − Z<br />

1 <br />

, C =<br />

¯Z<br />

L + Zg ¯ + Z¯g ¯<br />

− Z<br />

, a = b = c = F = G = 0 ,<br />

(3.16)<br />

<strong>with</strong> some arbitrary function g(Z). When inserted into the Ansatz (2.41), the gdependent<br />

terms can be written as<br />

¯Z i j<br />

¯Z<br />

D (g D Z) + ¯ i<br />

D (¯g ¯ j<br />

D Z) ¯ , (3.17)<br />

− Z<br />

and if there is a function f(Z) <strong>with</strong> ∂f = g, they simplify to<br />

¯Z i j<br />

¯Z<br />

D D f(Z) + ¯ i<br />

D ¯ j<br />

D f( ¯ Z) ¯ . (3.18)<br />

− Z<br />

We shall first consider the simplest case g = 0, which corresponds to the constraints<br />

D (i<br />

α ¯ D j)<br />

L = 0<br />

˙α<br />

D (i D j) L = 2<br />

¯Z − Z<br />

D (i Z D j) L + ¯ D (i ¯ Z ¯ D j) L + 1<br />

2 L Di D j Z .<br />

(3.19)<br />

In the limit Z = i they reduce to the free constraints (2.3). We return to g = 0 in<br />

section 3.4.<br />

3.2 Transformations and Bianchi Identities<br />

By construction, the constraints (3.19) satisfy the necessary consistency conditions<br />

(C.1–4). The task now is to solve, if possible, the Bianchi identities (BI.1) and (BI.2).<br />

Then we would have shown the constraints to be consistent and could proceed to<br />

determine the invariant action. To do this, we need to compute DαjM ij , DiDjM ij and<br />

¯D ˙αi ¯ DαjM ij , which suffices as in the case at hand M ij is imaginary and N ij<br />

α ˙α = 0, cf.<br />

section 2.2.<br />

In terms of component fields the deformation M ij reads<br />

M ij = − ¯ M ij = 1 (i j)<br />

λ ψ − ¯(i λ ¯j) ij<br />

ψ + iLY<br />

I<br />

. (3.20)<br />

Applying a supersymmetry generator Dαj and summing over j, we obtain<br />

DαjM ij = 3 <br />

Fµνσ<br />

2I<br />

µν ψ i + i<br />

2Gµνσ µν λ i + i<br />

2Wµσ µ¯i λ − i∂µ ¯ Zσ µ ψ¯ i ij<br />

+ Y ψj<br />

− Lσ µ ∂µ ¯ λ i − 1<br />

2 DµL σ µ¯ λ i − i<br />

2 ¯ ZUλ i + i λjM<br />

ij<br />

2 α ,<br />

(3.21)

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