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N=2 Supersymmetric Gauge Theories with Nonpolynomial Interactions

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46 Chapter 3. The Linear Case<br />

and L ij<br />

cc is the super Yang-Mills pre-Lagrangian as in eq. (1.44) <strong>with</strong> ∂F(Z) = f(Z).<br />

Without going into detail, the terms proportional to κ, which in the limit Z = i<br />

reduce to the real part of D i L D j L, can be shown to yield a Lagrangian that is a total<br />

derivative. Therefore we confine ourselves to κ = 0 in the following. The constant µ<br />

on the other hand can be removed by a shift of L, hence we also take µ = 0.<br />

This leaves the terms proportional to ϱ, where <strong>with</strong>out loss of generality we can take<br />

ϱ = 1. Actually, they constitute a linear superfield irrespective of the precise form of<br />

M ij as long as N ij<br />

α ˙α = 0 and ¯ M ij = −M ij , for we have<br />

D (i<br />

j k)<br />

α D L D L − D¯ j<br />

L D¯ k) j k)<br />

L + L D D L =<br />

= −2 D β(i L D j αD k)<br />

β L + D(i αL D j D k) L = 0 .<br />

For this reason we shall first compute the Lagrangian <strong>with</strong>out specifying M ij , the result<br />

of which then may also be used in the following section, where we extend the model by<br />

additional vector multiplets such that the properties of the deformations just mentioned<br />

are preserved.<br />

Let us consider therefore<br />

L ij = i ψ i ψ j − ¯ ψ i ψ¯ j ij<br />

− LM , M¯ ij ij ij<br />

= −M , Nα ˙α = 0 , (3.53)<br />

and work out the Lagrangian according to eq. (1.42), <strong>with</strong> the supersymmetry transformations<br />

given in section 2.2. The first step is to apply a supersymmetry generator<br />

Dαj to L ij ,<br />

DαjL ij = 3<br />

2<br />

<br />

¯ZUψ i<br />

− Gµνσ µν ψ i − (Wµ + iDµL)σ µ ψ¯ i ij<br />

− M ψj − 2iL<br />

DjM<br />

ij<br />

. (3.54)<br />

3 α<br />

Next we apply a second generator D α i , sum over α and i, multiply <strong>with</strong> Z/6 and take<br />

the real part of the result. We find after some algebra<br />

1<br />

12 Z DiDjL ij + c.c. = 1<br />

2 ID µ L DµL − W µ Wµ − 2i ψ i ↔<br />

µ<br />

σ ∂µ ¯ ψi + |Z| 2 U 2<br />

− 1<br />

4 Gµν (IGµν − R ˜ Gµν) − RW µ DµL + R ∂µ(ψ i σ µ ψi) ¯<br />

− U( ¯ Zλiψ i − Z¯ λ i ψi) ¯ + iAµU(ψ i σ µ¯ λi − λ i σ µ ψi) ¯ (3.55)<br />

+ iAµ(ψiσ µ ¯σ ν Dνψ i + ¯ ψ i ¯σ µ σ ν Dν ¯ ψi) + 1<br />

4 IM ij Mij<br />

− i<br />

12 LZ DiDj + ¯ Z ¯ Di ¯ ij 2i<br />

Dj M −<br />

3 I(ψiDj + ¯ ψi ¯ Dj)M ij<br />

+ i<br />

3 Aµ(ψiσ µ Dj<br />

¯ + ¯ ψi¯σ µ Dj)M ij .<br />

We already recognize the properly normalized kinetic terms for L and ψ i , keeping in<br />

mind that 〈I〉 = 1. The naked gauge field Aµ appears due to the splitting of the<br />

covariant derivative of ψ i as in the calculation leading to eq. (2.33). It remains to

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