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download pdf version of PhD book - Universiteit Utrecht

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5. Pore-Network Modeling <strong>of</strong> Two-Phase Flow<br />

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .<br />

where A and P are the area and the perimeter <strong>of</strong> the cross section, respectively.<br />

The shape factor replaces the irregular and complicated shape <strong>of</strong> a pore throat<br />

by an equivalent irregular, but simpler, shape. The value <strong>of</strong> shape factors<br />

for pore throats are chosen from a truncated lognormal distribution (Equation<br />

5.1), with a minimum shape factor value <strong>of</strong> zero corresponding to a slit, and<br />

a maximum value <strong>of</strong> 0.08 corresponding to a circular cross section. Values<br />

between zero and 0.048 correspond to triangular cross sections (with maximum<br />

value <strong>of</strong> 0.048 for an equilateral triangle), and values between zero and 0.062<br />

correspond to rectangular cross section (with the maximum value corresponding<br />

to a square).<br />

For a triangular cross section, there is a relationship between shape factor and<br />

corner angles [Patzek, 2001], given by<br />

G = A P 2 = 1<br />

∑<br />

4 3 cot(Angle i )<br />

i=1<br />

= 1 tan α tan β cot(α + β) (5.3)<br />

4<br />

where α and β are the two corner half-angles subtended by the two longest<br />

sides <strong>of</strong> the triangle. It is clear from the above equation that for a single value<br />

<strong>of</strong> the shape factor, a range <strong>of</strong> corner half angles are possible. We follow the<br />

procedure employed by Patzek [2001] to select a nonunique solution for corner<br />

half-angles. We start by selecting the upper and lower limits <strong>of</strong> the corner<br />

half-angle, β, assuming β < α. These two limits are<br />

[ ( ( √ ) )]<br />

2 arccos −12 3G<br />

β min = arctan √ cos<br />

+ 4π 3 3<br />

3<br />

[ ( ( √ ))]<br />

2 arccos −12 3G<br />

β max = arctan √ cos 3 3<br />

(5.4)<br />

(5.5)<br />

We randomly pick a value, β = β min + (β max − β min ) .ϕ, between the two<br />

limits. Where ϕ is a uniformly distributed random number, between 0 and 1.<br />

We calculate the corresponding value <strong>of</strong> α by inverting Equation (5.3)<br />

α = − 1 2 β + 1 2 arcsin ( tan β + 4G<br />

tan β − 4G sin β )<br />

(5.6)<br />

The third and smallest corner half-angle, γ, is then obtained from γ = π 2 −<br />

(α + β). After determining the corner angles, finding the triangle size requires<br />

specifying a length scale. We have chosen the radius <strong>of</strong> the equivalent circle<br />

<strong>of</strong> a pore cross section as the length scale. One way to select this radius is<br />

98

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