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4.3 Simulating flow and transport within the network<br />

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .<br />

Figure 4.3: An example <strong>of</strong> interconnected pore bodies and pore<br />

throats. Flow direction is from pore body j into pore body i in tube<br />

ij. Node j is the upstream node.<br />

We assume that each pore body and pore throat is a fully mixed domain.<br />

Therefore, a single concentration is assigned to each pore body or pore throat<br />

[De Jong, 1958, Li et al., 2007b]. For a given pore body, i, (e.g., in Figure 4.3)<br />

we can write the mass balance equation<br />

N<br />

dc<br />

in<br />

i<br />

V i<br />

dt = ∑<br />

q ij c ij − Q i c i (4.4)<br />

j=1<br />

where c i is the pore-body average mass concentration, c ij is the pore-throat<br />

average mass concentration, Q i is the total water flux leaving the pore body,<br />

V i is the volume <strong>of</strong> pore body i, and N in is the number <strong>of</strong> pore throats flowing<br />

into pore body i. As the total water flux entering a pore body is equal to the<br />

flux leaving it, we have<br />

∑N in<br />

Q i = q ij (4.5)<br />

j=1<br />

Note that, in Equation (4.4), we have neglected adsorption <strong>of</strong> solutes to the<br />

pore body walls. Adsorption <strong>of</strong> the solutes to the walls <strong>of</strong> the pore throats is<br />

taken into account as explained below. At the local-scale, i.e., at the wall <strong>of</strong><br />

the pore throats, the solute adsorption is assumed to occur as an equilibrium<br />

process. Assuming linear equilibrium, we may write s = k d c| wall<br />

, where s is<br />

the adsorbed concentration at the grain surface [ML −2 ], c| wall<br />

[ML −3 ] is the<br />

solute concentration in the fluid phase next to the wall, and k d [L] denotes the<br />

75

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