Spin-orbit coupling and electron-phonon scattering - Fachbereich ...
Spin-orbit coupling and electron-phonon scattering - Fachbereich ...
Spin-orbit coupling and electron-phonon scattering - Fachbereich ...
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1.3 Rashba effect in a perpendicular magnetic field 13<br />
effect. Any effect which leads to a B = 0 spin splitting (like BIA) may also result<br />
in a beating pattern.<br />
1.3 Rashba effect in a perpendicular magnetic field<br />
In the following, we present the effect of an additional perpendicular magnetic<br />
field which is a common tool to introduce a tuneable energy scale, i.e. the cyclotron<br />
energy ω c = eB/mc. In addition to this energy scale, which finally<br />
leads to the quantisation of the system into L<strong>and</strong>au levels, the Zeeman effect is<br />
also expected to alter the spin state of the <strong>electron</strong>s.<br />
This system serves as an example for the interplay of the Rashba effect with<br />
a further energy scale. Furthermore, it shows an illustrative analogy to a quantum<br />
optical model which will be useful in the following chapters of the thesis when<br />
dealing with non-integrable models.<br />
We extend the Hamiltonian (1.3) of the previous section by including a perpendicular<br />
magnetic field (B = B ê z ),<br />
H = H 0 + H SO , (1.7)<br />
H 0 = 1 (<br />
p + e ) 2<br />
2m c A 1 +<br />
2 gµ BBσ z , (1.8)<br />
H SO = − α [(p + e ) ]<br />
c A × σ , p = (p x, p y ). (1.9)<br />
z<br />
We follow the st<strong>and</strong>ard derivation of quantised L<strong>and</strong>au levels in symmetric gauge<br />
A = (−y,x)B/2, by defining<br />
x ± = 1 √<br />
2<br />
(y ± ix), p ± = 1 √<br />
2<br />
(p y ∓ ip x ), (1.10)<br />
<strong>and</strong> creation <strong>and</strong> annihilation operators<br />
(<br />
1<br />
a = √ p − − i mωc 2 mω cx +<br />
),<br />
(<br />
a † 1<br />
= √ p + + i mωc 2 mω cx −<br />
), (1.11)<br />
leading to the representation in terms of L<strong>and</strong>au levels,<br />
(<br />
H 0<br />
= a † a + 1 )<br />
+ 1 ω c 2 2 δσ z, (1.12)<br />
with the dimensionless Zeeman splitting δ = mg/2m 0 , (m 0 : bare mass of <strong>electron</strong>).<br />
Expressing the SO <strong>coupling</strong> in the same representation gives<br />
H SO<br />
= 1 l<br />
(<br />
√ B<br />
aσ + + a † σ −<br />
), σ ± = 1 ω c 2 l SO 2 (σ x ± iσ y ), (1.13)