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Spin-orbit coupling and electron-phonon scattering - Fachbereich ...

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1.3 Rashba effect in a perpendicular magnetic field 13<br />

effect. Any effect which leads to a B = 0 spin splitting (like BIA) may also result<br />

in a beating pattern.<br />

1.3 Rashba effect in a perpendicular magnetic field<br />

In the following, we present the effect of an additional perpendicular magnetic<br />

field which is a common tool to introduce a tuneable energy scale, i.e. the cyclotron<br />

energy ω c = eB/mc. In addition to this energy scale, which finally<br />

leads to the quantisation of the system into L<strong>and</strong>au levels, the Zeeman effect is<br />

also expected to alter the spin state of the <strong>electron</strong>s.<br />

This system serves as an example for the interplay of the Rashba effect with<br />

a further energy scale. Furthermore, it shows an illustrative analogy to a quantum<br />

optical model which will be useful in the following chapters of the thesis when<br />

dealing with non-integrable models.<br />

We extend the Hamiltonian (1.3) of the previous section by including a perpendicular<br />

magnetic field (B = B ê z ),<br />

H = H 0 + H SO , (1.7)<br />

H 0 = 1 (<br />

p + e ) 2<br />

2m c A 1 +<br />

2 gµ BBσ z , (1.8)<br />

H SO = − α [(p + e ) ]<br />

c A × σ , p = (p x, p y ). (1.9)<br />

z<br />

We follow the st<strong>and</strong>ard derivation of quantised L<strong>and</strong>au levels in symmetric gauge<br />

A = (−y,x)B/2, by defining<br />

x ± = 1 √<br />

2<br />

(y ± ix), p ± = 1 √<br />

2<br />

(p y ∓ ip x ), (1.10)<br />

<strong>and</strong> creation <strong>and</strong> annihilation operators<br />

(<br />

1<br />

a = √ p − − i mωc 2 mω cx +<br />

),<br />

(<br />

a † 1<br />

= √ p + + i mωc 2 mω cx −<br />

), (1.11)<br />

leading to the representation in terms of L<strong>and</strong>au levels,<br />

(<br />

H 0<br />

= a † a + 1 )<br />

+ 1 ω c 2 2 δσ z, (1.12)<br />

with the dimensionless Zeeman splitting δ = mg/2m 0 , (m 0 : bare mass of <strong>electron</strong>).<br />

Expressing the SO <strong>coupling</strong> in the same representation gives<br />

H SO<br />

= 1 l<br />

(<br />

√ B<br />

aσ + + a † σ −<br />

), σ ± = 1 ω c 2 l SO 2 (σ x ± iσ y ), (1.13)

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