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multivariate poisson hidden markov models for analysis of spatial ...

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3.2.2 Problem 2 and its solution<br />

Given a sequence <strong>of</strong> observations Y = { Y1, Y2,..., Y T<br />

} and the model λ , we want to find<br />

the most likely state sequence associated with the given observation sequence.<br />

The solution to this problem depends on the way “the most likely state sequence” is<br />

defined. One method is to find the most likely state S<br />

t<br />

at time t and to concatenate all<br />

such S t<br />

’s. However, sometimes this approach does not give a physically meaningful<br />

state sequence. The most widely used criterion is to maximize P[ Y= y, S=<br />

s ; λ]<br />

. That is,<br />

to maximize the probability <strong>of</strong> observing observation sequence Y = Y , Y ,..., Y } and<br />

the state sequence S = { S1,..., S T<br />

} given their joint distribution f ( ys , ).<br />

{<br />

1 2 T<br />

Since the model λ = ( A,<br />

B,<br />

π ) and the observation sequence is Y = Y , Y ,..., Y }, the<br />

{<br />

1 2 T<br />

probability <strong>of</strong> the state path and observation sequence given the model would be:<br />

P[ Y= y, S= s; λ] = P[ Y= y| S= s; λ] P[ S=<br />

s ; λ]<br />

= π b ( y ) P b ( y )... P b ( y ). (3.10)<br />

S1 S1 1 S1S2 S2 2 ST−1ST ST<br />

T<br />

To write this in a <strong>for</strong>m <strong>of</strong> summations, we define U (s)<br />

as<br />

U ( s ) = − ln( P[<br />

Y = y,<br />

S = s;<br />

λ])<br />

T<br />

=− [ln( π b ( y )) +∑ ln( P b ( y ))] . (3.11)<br />

S1 S1 1<br />

St−1St St<br />

t<br />

t 2<br />

=<br />

Since ln() is monotonic function if − ln( P[ Y= y, S=<br />

s; λ])<br />

is minimum, then this will give<br />

us the state sequence <strong>for</strong> P[ Y= y, S=<br />

s ; λ]<br />

is maximum. There<strong>for</strong>e,<br />

35

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