Synergy User Manual and Tutorial. - THE CORE MEMORY
Synergy User Manual and Tutorial. - THE CORE MEMORY
Synergy User Manual and Tutorial. - THE CORE MEMORY
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<strong>Synergy</strong> <strong>User</strong> <strong>Manual</strong> <strong>and</strong> <strong>Tutorial</strong><br />
S<br />
=<br />
performance _ with _ improvement<br />
performance _ without _ improvement<br />
100<br />
= = 1.333<br />
75<br />
If a computation is improved such that it affects a proportion F p of the computation, then<br />
the improvement will have a speedup S affecting F p . The improved time for a<br />
computation will be equal to the unimproved time multiplied by the sum of the<br />
unaffected portion (1-F p ) <strong>and</strong> the speedup reduced affected portion (F p ÷S) of the task. To<br />
find the improved execution time we use:<br />
⎡<br />
improved _ time = unimproved _ time ×<br />
⎣<br />
F<br />
p ⎤<br />
⎢( 1−<br />
Fp<br />
) + ⎥ ⎦<br />
Continuing the formula above with an affected portion of 40 percent <strong>and</strong> a speedup of<br />
2.66 times on this portion, we have:<br />
⎡ 0.4 ⎤<br />
improved _ time = 4×<br />
⎢<br />
=<br />
⎣ 2.66⎥<br />
⎦<br />
( 1−<br />
0.4) + = 4×<br />
( 0.6×<br />
0.15) = 4×<br />
0.75 3<br />
This method states, assuming that the value for the speed of the unimproved computation<br />
is 100 percent, the overall speedup for this computational improvement will be:<br />
S<br />
S<br />
unimproved _ time<br />
=<br />
improved _ time<br />
=<br />
(1 − F<br />
1<br />
p<br />
) +<br />
F<br />
S<br />
p<br />
Then plugging in the example proportional values:<br />
S<br />
1<br />
=<br />
(1 − 0.4) +<br />
0.4<br />
2.66<br />
=<br />
1<br />
0.75<br />
= 1.33<br />
Using time values instead of proportions, we have:<br />
4sec<br />
S =<br />
1.6sec<br />
(4sec−1.6sec)<br />
+<br />
2.66<br />
=<br />
4sec<br />
3sec<br />
= 1.33<br />
102