Synergy User Manual and Tutorial. - THE CORE MEMORY
Synergy User Manual and Tutorial. - THE CORE MEMORY
Synergy User Manual and Tutorial. - THE CORE MEMORY
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<strong>Synergy</strong> <strong>User</strong> <strong>Manual</strong> <strong>and</strong> <strong>Tutorial</strong><br />
where S is the speedup, the serial portion is F s <strong>and</strong> N p is the number of processors.<br />
Again, assume that F s = 0.06. Then F p = 1–F s = 0.94. For 4 processors:<br />
S<br />
= N<br />
p<br />
p s<br />
+ ( 1−<br />
N ) × F = 4 + (1 − 4) × 0.06 = 4 − 0.18 = 3.82<br />
The table <strong>and</strong> graphs below show the same data as in Amdahl but using Gustafson’s law.<br />
Processors(N) 1 2 4 8 16 32 64 128 256 512 1024<br />
Run Time 1024.0000 527.8351 268.0628 135.0923 67.8146 33.9748 17.0043 8.5064 4.2543 2.1274 1.0638<br />
Speedup 1.0000 1.9400 3.8200 7.5800 15.1000 30.1400 60.2200 120.3800 240.7000 481.3400 962.6200<br />
Efficiency 100.00% 97.00% 95.50% 94.75% 94.38% 94.19% 94.09% 94.05% 94.02% 94.01% 94.01%<br />
Cost 1.0000 1.0309 1.0471 1.0554 1.0596 1.0617 1.0628 1.0633 1.0636 1.0637 1.0638<br />
4<br />
4<br />
16<br />
16<br />
65<br />
65<br />
3.95<br />
15.8<br />
64<br />
15.6<br />
4 ( 1 4) F<br />
3.9<br />
16 ( 1 16) F<br />
.<br />
64 1 F 64 ( )<br />
63<br />
15.4<br />
3.85<br />
15.2<br />
62<br />
3.82<br />
. 0.06<br />
3.8<br />
0 0.01 0.02 0.03 0.04 0.05 0.06<br />
0 F<br />
15.1<br />
. 0.06<br />
15<br />
0 0.01 0.02 0.03 0.04 0.05 0.06<br />
0 F<br />
61.16<br />
61<br />
0 0.01 0.02 0.03 0.04 0.05 0.06<br />
0 F<br />
0.06<br />
260<br />
256<br />
1040<br />
1.024 . 10 3<br />
255<br />
1020<br />
256 ( 1 256) F 250<br />
. 0.06<br />
1024 ( 1 1024) F1000<br />
. 0.06<br />
245<br />
980<br />
240.7 240<br />
0 0.01 0.02 0.03 0.04 0.05 0.06<br />
0 F<br />
Consider the following diagrams, which are similar to those in Gustafson’s paper:<br />
Time = s A + p A = 1<br />
s A<br />
p A<br />
Single Processor<br />
962.62<br />
960<br />
0 0.01 0.02 0.03 0.04 0.05 0.06<br />
0 F<br />
s A<br />
p A /N p<br />
N Processors<br />
Time = s A + p A /N p<br />
105
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