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THE EGS5 CODE SYSTEM

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2.11 Bhabha Scattering<br />

The differential Bhabha[25], cross section, as formulated in PEGS, is<br />

where<br />

d˘Σ Bhabha (Ĕ0)<br />

dĔ−<br />

= X 0n2πr 2 0 m<br />

˘T 2 0<br />

[ 1<br />

E<br />

( )<br />

]<br />

1<br />

Eβ 2 − B 1 + B 2 + E (EB 4 − B 3 )<br />

(2.208)<br />

Ĕ 0 = energy of incident positron (MeV),<br />

˘T 0 = kinetic energy of incident positron (MeV),<br />

β = v/c for incident positron,<br />

γ = Ĕ0/m,<br />

Ĕ − = energy of secondary electron (MeV),<br />

E = (Ĕ− − m)/ ˘T 0 = ˘T − / ˘T 0 ,<br />

y = 1/(γ + 1),<br />

B 1 = 2 − y 2 ,<br />

B 2 = (1 − 2y)(3 + y 2 ),<br />

B 3 = B 4 + (1 − 2y) 2 ,<br />

B 4 = (1 − 2y) 3 .<br />

If Equation 2.208 is integrated between Ĕ1 and Ĕ2, we obtain<br />

∫ Ĕ2<br />

Ĕ 1<br />

d˘Σ Bhabha (Ĕ0)<br />

dĔ−<br />

dĔ− = X 0n2πr 2 0 m<br />

˘T 2 0<br />

[ 1<br />

β 2 ( 1<br />

E 1<br />

− 1 E 2<br />

)<br />

− B 1 ln E 2<br />

+B 2 (E 2 − E 1 ) + E 2 2 (E 2B 4 /3 − B 3 /2) − E 2 1 (E 1B 4 /3 − B 3 /2)<br />

E 1<br />

]<br />

(2.209)<br />

where<br />

and other symbols are the same as in Equation 2.208.<br />

E i = (Ĕi − m)/ ˘T 0 , i = 1, 2 (2.210)<br />

Unlike in Møller scattering, in Bhabha scattering, the final state particles are distinguishable,<br />

so the upper limit for E is 1. Note that E is the fraction of the kinetic energy that the negative<br />

atomic electron gets. There is still a singularity at E = 0 which is circumvented in the same way as<br />

for Møller by requiring that the energy transfered to the atomic electron be at least T E = A E − m.<br />

It should be noted that there is no singularity at E = 1 as there was for Møller, and in fact, the<br />

final positron energy may be less than A E (down to m). Thus, the threshold for a discrete Bhabha<br />

interaction is A E , and as long as the positron is above the cutoff energy, it will have some non-zero<br />

Bhabha cross section. Using the minimum and maximum Ĕ− for Ĕ1 and Ĕ2 in Equation 2.209, we<br />

obtain the total cross section as<br />

˘Σ Bhabha (Ĕ0) = (Equation 2.209 with Ĕ1 = A E & Ĕ2 = Ĕ0 if Ĕ 0 > A E , 0). (2.211)<br />

68

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