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d� t<br />
dt � ��t �t � ��t �x<br />
dx<br />
dt � �� t<br />
�y<br />
dy<br />
dt � ��t �z<br />
– 5.46 –<br />
dz<br />
dt � 0 � �� t<br />
�t � u ��t t<br />
�x � v �� t<br />
t<br />
�y � wt (5.4)<br />
which is known as the kinematic condition. The above equation can be solved for � t by<br />
using a finite-volume technique on the 2D grid (xy plane) of the surface boundary. To<br />
avoid the excessive computational time, the surface computation can be carried out at the<br />
end of each time step. Alternatively, it can also be done after several time steps when the<br />
pressure correction has reduced to a sufficiently small number as in the case of the<br />
present model.<br />
The surface function, � t , is unfortunately given for the surface (top face) center, whereas<br />
the cell is defined by its vertices. This in effect necessitates the use of an interpolation to<br />
get the z values of the cell vertices from this function. The simplest approach will be<br />
using a linear interpolation (see Fig. 5.24c). Note that the usual notations PEWNS are<br />
used to indicate the center and neighboring nodes on the 2D mesh which constitutes the<br />
top boundary of the 3D mesh. Integrating Eq. 5.4 over the 2D cell and writing each term<br />
in the discretized finite-volume form, one has:<br />
�<br />
�t<br />
�� St, z<br />
�� St, z<br />
�� St, z<br />
��S<br />
t, z<br />
� t dS � �t,P n�1 n<br />
� � t,P<br />
St,z �t<br />
dS � �u t�<br />
�x<br />
n�1 n�1 n�1 n�1 n�1<br />
�� �t �y�<br />
� �<br />
e � t �y�<br />
� �<br />
w � t �y�<br />
� �<br />
n � t �y�s<br />
�<br />
�� t<br />
dS � �vt �<br />
�y<br />
n�1 n�1 n�1 n�1 n�1<br />
�� �t �x�<br />
� �<br />
e � t �x�<br />
� �<br />
w � t �x�<br />
� �t �x<br />
n � �s �<br />
��<br />
u t<br />
t<br />
v t<br />
w t dS � wt St,z (5.5)<br />
where the face values are obtained by interpolation (see Eq. 4.19), for example for the<br />
east face: � t,e � �1� �e�� t,P � �e � t,E . Using this interpolation to replace the face values<br />
in Eq. 5.5, the discretized finite-volume form of Eq. 5.4 is:<br />
n�1 n�1<br />
aP �t,P � � anb �t,nb � b (5.6)<br />
nb�EWNS<br />
where the coefficients consist of the following terms:<br />
aP � St,z �t � anb �<br />
nb<br />
� �ye � �yw � �yn � �y � s�u<br />
t � �xe � �xw � �xn � �xs aE � �e��ye ut � �xe vt�, aW � �w��y w ut � �xw vt�, aN � �n��y n ut � �xn vt�, aS � �s��y s ut � �xs vt �,<br />
b � w t S t,z � S t,z<br />
�t .<br />
� � v t ,