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a<br />

E E +<br />

a :mmr<br />

b<br />

Fig. 15.1. Schematic diagram<br />

of the electric field: a - for two Fig. 15.2. Uniform (a) and<br />

equal and opposite charges; nonuniform (b) electric field<br />

b - for point charges<br />

are related to the electric field in any region of space in the<br />

following manner:<br />

1. The electric field vector (E) is tangent to the electric field<br />

line at each point;<br />

2. The number of lines per unit area through a surface<br />

perpendicular to the lines is proportional to the strength of the<br />

electric field (or the magnitude of the charge) in that region.<br />

3. The lines must begin on positive charges and terminate on<br />

negative charges, or at infinity in the case of an excess of charge;<br />

4. No two field lines can cross.<br />

An important field for consideration is the uniform electric<br />

field (fig. 15.2, a); a field that has the same magnitude and direction<br />

at all points. In the opposite situation, the field is non-unifornm<br />

(fig. 15.2, b).<br />

15.2.4. Electric Potential<br />

Instead of dealing directly with the potential energy of a<br />

charged particle, it is useful to introduce the more general concept<br />

of energy per unit charge.<br />

Suppose a test charge (qo) moves from A to B under the influence<br />

of a field (E ). The work (dA) done by the electric force (qE) on<br />

the test charge for an infinitesimal displacement (di) is given by:<br />

114<br />

dA = F .dx = qoE .di: (15.4)<br />

By definition, the work done by a conservative force equals the<br />

negative of the change in potential energy (dU); therefore:<br />

dA = - dU = - qaE ·di (15.5)<br />

A force is conservative if the work done by the force acting on<br />

a particle moving between two points is independent of the path<br />

the particle takes between the points.<br />

For a finite displacement of the test charge between points<br />

A and B, the change in the potential energy is given by:<br />

-%I B U =U B<br />

-U A = j;·dX<br />

(15.6)<br />

A<br />

where U and U<br />

B A<br />

are the initial and final potential energies,<br />

respectively.<br />

The potential difference (,1cp) between points A and B is defined<br />

as the change in potential energy divided by the test charge (qo):<br />

U B U A<br />

ticp = cp E- dx<br />

B - CPA = - - - = -I . x (15.7)<br />

qo qo A<br />

The quantity which equals the energy per unit charge [rp = ~)<br />

is called the electric potential (U).<br />

qo<br />

The unit of potential is the Joule per Coulomb, which is equal<br />

to a volt (1 V = 1 J/c)·<br />

15.2.5. Obtaining E from the Electric Potential<br />

The electric field (E) and the potential (U) are related by<br />

Equation (15.7). To calculate the electric field if the electric potential<br />

is known in a certain region, apply Equation (15.7) when<br />

there is a uniform electric field:<br />

B B B<br />

L1 qJ = - IE. dx = - I E cos OOds = - IEds (15.8)<br />

A A • A<br />

Since E is constant, it can be removed from the integral sign,<br />

giving:<br />

B<br />

115

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