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Abelian Groups - László Fuchs [Springer]

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192 6 Algebraically Compact <strong>Groups</strong><br />

Proof. Apply the preceding corollary to B D Ker , and note that A= Ker is<br />

complete by virtue of Lemma 7.2 in Chapter 2.<br />

ut<br />

Lemma 2.8 (Kaplansky [K]). Let G be a pure subgroup of a complete group C.<br />

Then the Z-adic closure of G in C is a summand of C. In particular, a pure closed<br />

subgroup is a summand.<br />

Proof. A basic subgroup B 0 of G extends to a basic subgroup B D B 0 ˚ B 00 of C.<br />

Then C D QB 0 ˚ QB 00 by Theorem 2.4,whereG QB 0 . Thus QB 0 is the closure of G in C.<br />

ut<br />

Completions We turn our attention to the completion process. In the next result<br />

we expand Theorem 7.7(i) in Chapter 2.<br />

Theorem 2.9. For any group A, the inverse limit<br />

QA D lim.A=nA/<br />

with the connecting maps a C knA 7! a C nA .a 2 AI n; k 2 N/ is a complete group.<br />

The canonical map<br />

A W a 7! .:::;a C nA;:::/2 QA<br />

has A 1 for its kernel, and an isomorphic copy of A=A 1 for its image. A .A/ is pure<br />

in QA, and the factor group QA= A .A/ is divisible.<br />

Proof. Since the factor groups A=nA are bounded, and hence complete, Q .A=nA/<br />

is complete, and its pure closed subgroup (the inverse limit) is complete by<br />

Lemma 2.8. Clearly, a D 0 amounts to a 2 nA for every n, whence Ker D A 1<br />

and Im Š A=A 1 .IfQb D .:::;b n C nA;:::/.b n 2 A/ satisfies mQb D a for some<br />

a 2 A and m 2 N, thenmb n a 2 nA for every n, in particular, for n D m, whence<br />

a 2 mA, and the purity of A in QA follows. To prove that QA=A is divisible, we show<br />

that every Qb D .:::;b n C nA;:::/ .b n 2 A/ is divisible by every m 2 N mod A.<br />

Since mjb m b km for each k 2 N,wehavemjQb b m , in fact. ut<br />

An immediate consequence of the preceding theorem is the inequality<br />

j QAj jAj @ 0<br />

; (6.6)<br />

which is evident in view of QA Q n A=nA.<br />

The group QA is called the Z-adic completion of A. Themap A W A ! QA is<br />

natural in the categorical sense, so the correspondence A 7! QA is functorial. Indeed,<br />

we have<br />

Proposition 2.10. Every homomorphism ˛ W A ! B induces a unique QZhomomorphism<br />

Q˛ W QA ! QB making the diagram

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