24.11.2017 Views

Abelian Groups - László Fuchs [Springer]

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

5 The Functor Pext 275<br />

F Notes. Lemma 4.4 was published by Eklof–<strong>Fuchs</strong> [Annali Mat. Pura Appl. 90, 363–374<br />

(1988)] for the special case (on valuation domain) needed there.<br />

Let us call attention to the basic difference between Lemmas 4.3 and 4.4. In the former lemma,<br />

the second argument of Ext was kept fixed, while in the latter lemma the second argument could<br />

grow as large as necessary to match the size of the group in the first argument. This explains why<br />

we needed the Diamond Principle in one case, but not in the other, this difference will be more<br />

apparent in Sect. 7 in Chapter 13.<br />

Exercises<br />

(1) Suppose that A satisfies Ext.X; A/ D 0 for all rank 1 torsion-free groups X.<br />

Then Ext.C; A/ D 0 for all torsion-free groups C.<br />

(2) If Ext.Z.p/; A/ D 0 holds for A, then Ext.C; A/ D 0 for all p-groups C.<br />

(3) If A satisfies Ext.Z.p/; A/ D 0 for all primes p,thenA is divisible.<br />

(4) Derive Pontryagin’s Theorem 7.1 in Chapter 3 from Lemma 4.1.<br />

(5) (Eklof–Huber) If C is a torsion-free group of countable rank such that<br />

Ext.B; A/ D 0 holds for all finite rank subgroups B < C, then also<br />

Ext.C; A/ D 0 for any A.<br />

5 The Functor Pext<br />

That the extensions of A by C in which A is a pure subgroup (we will call them pureextensions)<br />

play a distinguished role does not seem to be obvious at the outset. The<br />

truly significant thing here is that these extensions form a subgroup of Ext which<br />

can be identified as the first Ulm subgroup of Ext.<br />

Preliminary Lemma We recall that if ˛ W A ! A and W C ! C are<br />

endomorphisms, then there are induced endomorphisms ˛ and of Ext.C; A/.<br />

We begin with investigating the actions of ˛ and in Ext.C; A/. In the proof of<br />

the next lemma, conveniently we may view A as a subgroup of B.<br />

Lemma 5.1 (Baer [4]). Given the exact sequence<br />

eW 0 ! A ! B ˇ<br />

! C ! 0 (9.16)<br />

and the endomorphisms ˛ W A ! A and W C ! C, we have:<br />

(i) e 2 Im ˛ if and only if A=˛A is a summand of B=˛A;<br />

(ii) e 2 Im if and only if A is a summand of ˇ 1 Ker ;<br />

(iii) if Ker D 0,thene 2 Ker if and only if ˇ 1 Im Š A ˚ Im .

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!