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Abelian Groups - László Fuchs [Springer]

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344 11 p-<strong>Groups</strong> with Elements of Infinite Height<br />

In other words, a has the maximal height in its coset mod G. Thus an element a 2 A<br />

of height is proper with respect to G if and only if a … p C1 A C G. In this case,<br />

h A .a/ D h A=G .a C G/:<br />

Of course such an element a need not exist in a coset, though it can be shown easily<br />

that if the height of a coset a C G in A=G is a non-limit ordinal, then the coset does<br />

contain an element of this height. Note that if a is proper with respect to G,thenwe<br />

have<br />

h.a C g/ D minfh.a/; h.g/g for all g 2 G:<br />

Evidently, if G is finite, then every coset mod G contains elements proper with<br />

respect to G. The same holds if G D p A for an ordinal .<br />

Let now A be a reduced p-group, and G a subgroup of A. For an ordinal , we<br />

introduce the notation<br />

G./ D .p C1 A C G/ \ p AŒpI<br />

this is a subgroup between p AŒp and p C1 AŒp. From our remark above it follows<br />

that an element a 2 A of order p and of height belongs to G./ if and only if it is<br />

not proper with respect to G. Consequently, representatives of the non-zero cosets<br />

in the factor group<br />

f .A; G/ D p AŒp=G./<br />

are exactly the elements of A that are of order p, of height , and proper with respect<br />

to G. ThisZ=pZ-vector space is called the th UK-invariant of A relative to G<br />

or the th Hill invariant of A relative to G. Sometimes we understand by this<br />

invariant the dimension of the vector space. We can allow this ambiguity, since from<br />

the context it will always be clear what we mean: vector space or its dimension.<br />

Evidently, f .A; G/ f .A/ and f .A;0/ D f .A/: Here f .A/ D p AŒp=p C1 AŒp<br />

is the Ulm-Kaplansky- or UK-invariant of A.<br />

Example 1.1. Let A D Z.p nC1 / and G D pA. ThenG.k/ D p k AŒp D AŒp for k D 0;:::;n, and<br />

G.k/ D 0 for all k > n. Thus the Hill invariants f .A; G/ vanish for all .<br />

Example 1.2. Let A be a reduced p-group, and B its basic subgroup. Then B.n/ D .p nC1 A C<br />

B/ \ p n AŒp D A \ p n AŒp D p n AŒp, thus f n .A; B/ D 0 for all n

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