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Abelian Groups - László Fuchs [Springer]

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488 13 Torsion-Free <strong>Groups</strong> of Infinite Rank<br />

the B i are isomorphic, and the C i are non-isomorphic (<strong>Fuchs</strong> [17]). The proofs rely on the existence<br />

of rigid systems of cardinality . A consequence is that there exist connected compact abelian<br />

groups of cardinality 2 admitting 2 non-isomorphic closed summands which are algebraically<br />

all isomorphic.<br />

Honestly, for uncountable torsion-free groups, anomaly in direct decompositions is less<br />

exciting, since their size makes it easier to use fancy constructions. However, there are certain<br />

limitations. For instance, Kaplansky’s theorem that summands of direct sums of countable groups<br />

are again direct sums of countable groups makes it impossible to have A D B ˚ C D ˚i A i<br />

with indecomposable summands, where jAj D@ 1 and the A i are of finite or countable ranks. A<br />

surprising example is a torsion-free group which is both the countable direct sum and the countable<br />

direct product of copies of the very same group; see Eda’s Proposition 4.9.<br />

Göbel–Ziegler [1] prove that, for every infinite cardinal , there exist groups of cardinality <br />

that decompose into the direct sum of non-zero summands for each 1<br />

is relevant.<br />

(c) Part (a) fails to hold if the components are not all of finite rank.<br />

(3) (Corner) There are countable torsion-free groups A; B; C such that A Š B ˚ C;<br />

B Š A ˚ C; but A and B are not isomorphic. [Hint: choose m D 2 in Theorem<br />

1.6.]<br />

(4) (Corner) There exists a countable torsion-free group A such that A is isomorphic<br />

to the direct sum of any finite number of, but not to the direct sum of infinitely<br />

many copies of itself.<br />

(5) If A is superdecomposable, then so are the groups A ./ for every cardinal .<br />

[Hint: direct sums of groups in Theorem 1.5; prove this for a finite sum, a<br />

countable sum, and apply Theorem 2.5 in Chapter 2.]

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