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Abelian Groups - László Fuchs [Springer]

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2 Slender <strong>Groups</strong> 489<br />

(6) A torsion-free group of infinite rank is a subdirect product of copies of Q.<br />

(7) (Reid) Every torsion-free group of infinite rank is a sum of two free groups.<br />

2 Slender <strong>Groups</strong><br />

A remarkable class of torsion-free groups was discovered by J. Łoś in the 1950s:<br />

the class of slender groups. Without further ado, we embark on their very attractive<br />

theory.<br />

Let P denote the direct product of a countable set of infinite cyclic groups, and S<br />

its subgroup that is the direct sum of the same groups:<br />

1Y<br />

P D he n i;<br />

nD1<br />

1M<br />

S D he n i;<br />

nD1<br />

where he n iŠZ:<br />

The elements of P can be written as formal infinite sums: x D P 1<br />

nD1 k ne n ,oras<br />

infinite vectors, like x D .k 1 e 1 ;:::;k n e n ;:::/, or else simply as x D .k 1 ;:::;k n ;:::/,<br />

where k n 2 Z.<br />

Slenderness A group G is called slender if, for every homomorphism<br />

W P ! G, wehavee n D 0 for almost all indices n. From this definition it<br />

is evident that the following hold true:<br />

(a) Subgroups of slender groups are slender.<br />

(b) The group P is not slender.<br />

(c) No injective group ¤ 0 is slender, so slender groups are reduced.<br />

(d) The group J p of p-adic integers, and more generally, an algebraically compact<br />

group ¤ 0, is not slender. In fact, the free group S can be mapped into J p by a<br />

homomorphism such that e n ¤ 0 for all n. SinceS is pure in P, andJ p is<br />

algebraically compact, extends to a map W P ! J p with e n ¤ 0 for all n.<br />

(e) Slender groups are torsion-free. The argument in (d) works for Z.p/ (for any<br />

prime p), since it is algebraically compact. A slender group cannot contain a<br />

non-slender Z.p/, so it must be torsion-free.<br />

The following lemma is a consequence of our remarks.<br />

Lemma 2.1. If W P ! G with G slender, then S D 0 implies D 0.<br />

Homomorphic image of P in a slender group is a finitely generated free group.<br />

Proof. If is as stated, then Im is an epic image of the algebraically compact<br />

group P=S, so it is a cotorsion group. A torsion-free cotorsion group is algebraically<br />

compact. No such group can be a subgroup of G, hence Im D 0. The second claim<br />

is a simple corollary to the first, using the definition of slenderness.<br />

ut

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