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Abelian Groups - László Fuchs [Springer]

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1 Freeness and Projectivity 77<br />

Corollary 1.4. Every group with at most generators is an epimorphic image of a<br />

free group with generators.<br />

ut<br />

Consequently, every group A can be embedded in a short exact sequence<br />

0 ! H ! F !A ! 0;<br />

where F is free group, and H D Ker . (We will see shortly that H is likewise free.)<br />

This is called a free resolution of A. It is far from being unique, because both F and<br />

can be chosen in many ways.<br />

If is an infinite cardinal, then F has 2 subsets, and hence at most 2 subgroups<br />

and factor groups. We conclude that there exist at most 2 pairwise non-isomorphic<br />

groups of cardinality . (We will learn in Corollary 3.8 in Chapter 11, that2 is<br />

the precise number.)<br />

The next two theorems are fundamental, they are quoted most frequently.<br />

Theorem 1.5. Suppose that B is a subgroup of a group A such that A=B isafree<br />

group. Then B is a summand of A, i.e., A D B ˚ C for a subgroup C Š A=B.<br />

Proof. That only free factor groups can share the stated property will follow<br />

from Theorem 1.7. In order to show that free groups do have this property,<br />

by Lemma 2.4 in Chapter 2, it suffices to verify the claim for A=B Š Z only, say<br />

A=B D ha C Bi with a 2 A. The elements of A=B are the cosets n.a C B/ D<br />

na C B .n 2 Z/ (all different). Hence A D B ˚hai is immediate.<br />

ut<br />

This theorem can also be phrased by saying that an exact sequence 0 ! B !<br />

A ! F ! 0 with a free group F is necessarily splitting.<br />

Subgroups of Free <strong>Groups</strong> In the next theorem we study the subgroups of free<br />

abelian groups. Recall the famous result in group theory that subgroups of (noncommutative)<br />

free groups are again free. For abelian groups the situation is the<br />

same. To prove this, we use a well ordering of the index set.<br />

Theorem 1.6. Subgroups of free groups are free.<br />

Proof. Let F be a free group on the set X, which we now assume to be well ordered,<br />

say X Dfx g < for some ordinal . Thus F D˚< hx i.For < ,define<br />

F D˚< hx i,andsetG D G \ F for a subgroup G < F. Clearly, G D<br />

G C1 \ F ,soG C1 =G Š .G C1 C F /=F . The last factor group is a subgroup<br />

of F C1 =F Šhx i; thus either G C1 D G or G C1 =G is an infinite cyclic group.<br />

From Theorem 1.5 we conclude that G C1 D G ˚hg i for some g 2 G C1<br />

(which is 0 if G C1 D G ). It follows that the elements g generate the direct sum<br />

˚< hg i in G. This must be all of G, sinceG is the union of the G . < /. ut

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