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Abelian Groups - László Fuchs [Springer]

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5 Vector <strong>Groups</strong> 511<br />

Isomorphism of Vector <strong>Groups</strong> At this point the natural question is: when are<br />

two vector groups isomorphic? To answer this question, we prove the following<br />

theorem. We denote by t 0 the largest idempotent type with t 0 t,i.e.t 0 D t W t.<br />

Theorem 5.5. Suppose<br />

V D Y t V t and W D Y t W t<br />

are vector groups where V t and W t are elementary vector groups of type t, and t<br />

runs over the different types.<br />

(i) (Sa¸siada [3]) V Š W if and only if V t Š W t for every type t.<br />

(ii) If V t D Q i2I R i Š W t D Q j2J R j with a type t 6Š t.Q/, thenjIj DjJj whenever<br />

I or J is non-measurable.<br />

Proof.<br />

(i) The “if” part being obvious, assume there is an isomorphism W V ! W. Let<br />

t W V ! V t and t W W ! W t denote the coordinate projections in the two<br />

direct products. By Lemma 5.4, every homomorphism of V t into W s is trivial<br />

unless the types satisfy s t. Therefore, V t Q st W s.Ifv 2 V t ,then<br />

v D w C w 0 with w 2 W t and w 0 2 Q s>t W s: AgainbyLemma5.4, the<br />

last group has only the trivial homomorphisms into V t and into W t , whence<br />

t 1 w 0 D 0 D t w 0 follows. This shows that v D t v D t 1 w and w D<br />

t w D t v; consequently, the map t 1 t is the identity on V t . Changing<br />

the roles of V t and W t , the stated isomorphism is immediate.<br />

(ii) Let R and R 0 be rational groups of types t and t 0 , respectively. In view<br />

of Corollary 2.10, wehaveHom.V t ; R/ Š ˚i2I Hom.R i ; R/ D ˚i2I R 0 and<br />

Hom.W t ; R/ Š ˚j2J R 0 . Both are completely decomposable groups whence<br />

V t Š W t implies jIj D jJj. ((ii) holds also for measurable index sets,<br />

see Theorem 6.1 below.)<br />

ut<br />

Summands of Non-measurable Vector <strong>Groups</strong> One of the most interesting<br />

facts on vector groups is concerned with direct summands in the non-measurable<br />

case.<br />

Theorem 5.6 (O’Neill [2]).<br />

(i) Summands of reduced vector groups are direct products of summands of<br />

elementary vector groups of different types.<br />

(ii) (Balcerzyk–Bialynicki-Birula–Łoś[1])Summands of reduced non-measurable<br />

vector groups are again vector groups.<br />

Proof.<br />

(i) Let V D Q t V t with elementary vector groups V t of type t. The projections in<br />

this decomposition will be denoted by t . For each type t, the subgroups<br />

V t D Y st<br />

V s and V t D Y s>t<br />

V s<br />

are fully invariant, and satisfy V t D V t ˚ V t .

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