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Esercizi svolti di analisi reale e complessa - Dipartimento di ...

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|f(x) − f(y)| ≤<br />

<br />

<br />

<br />

<br />

2<br />

1 1<br />

<br />

− + sin<br />

2 − |x| 2 − |y|<br />

≤ |x − y| 2 + n|x − y| 2 = √ n + 1 |x − y| .<br />

<br />

L = √ n + 1 .<br />

<br />

n<br />

i=1<br />

Ω = B1(x0)<br />

x0 = (2, . . . , 2)<br />

x ∈ Ω <br />

<br />

αn := 2 −<br />

<br />

n = 1, 2 αn, βn > 0<br />

2 √ n − 1 ≤ |x| ≤ 2 √ n + 1<br />

xi<br />

<br />

<br />

<br />

<br />

−<br />

<br />

<br />

<br />

<br />

sin<br />

n<br />

<br />

2 √ n + 1 ≤ 2 − |x| 1<br />

<br />

2 ≤ 2 − 2 √ n − 1 =: βn .<br />

i=1<br />

yi<br />

2<br />

<br />

<br />

≤<br />

<br />

n = 3, 4, 5, 6 αn < 0 < βn f <br />

Ω n = 4 <br />

x0<br />

n ≥ 7 αn, βn < 0<br />

n = 3, 4, 5, 6 <br />

α 2 n ≤ (2 − |x| 1<br />

2 )(2 − |y| 1<br />

2 ) ≤ β 2 n .<br />

In = (2 √ n−1, 2 √ n+1) <br />

<br />

s, t ∈ In <br />

| √ s − √ t| ≤<br />

=<br />

<br />

sup<br />

ξ∈In<br />

1<br />

2 √ <br />

|s − t| =<br />

ξ<br />

1<br />

2(2 √ |s − t| .<br />

n − 1)

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