Mechanik 1 - TU Wien

N a
M a = 0
4 Statik einfacher Tragwerke Mechanik 1
II :
I − 2 · II :
II :
2A H − A V = −p · 8.0 = −8
− 3A H = −20 + 16 = 4 → A H = 4 3 = 1.33kN
A V = 2A H + 8 = 10.67kN
b) Schnittgrößen
Punkt a
A H
a
Q a
Q a = −A H = −1.33kN
N a = −A V = −10.67kN
A V
Punkt c (l)
p
M (l)
c
N (l)
c
Q (l)
c
M (l)
c
= −A H · 8.0 − p · 8.0 · 4.0 = −42.64kNm
Q (l)
c
= −A H − p · 8.0 = −9.33kN
N (l)
c
= −A V = −10.67kN
a
A H
A V
Punkt c (r)
p
c
M (r)
c
Q (r)
c
N (r)
c
M (r)
c
Q (r)
c
= M (l)
c
N (r)
c
= −N (l)
c
= Q (l)
c
= −42.64kNm
= 10.67kN
= −9.33kN
a
A H
A V
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