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guidance, flight mechanics and trajectory optimization

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Ii--<br />

From this sketch, the following differential equations can be written for<br />

the motion of the vehicle<br />

<strong>and</strong><br />

*= - La+ u,<br />

V<br />

where T = the maximum thrust available<br />

max<br />

V = the exhaust velocity of the rocket.<br />

(2.2.10)<br />

(2.2.11)<br />

(2.2.12)<br />

There are several ways to formulate this problem for a Dynamic Programming<br />

solution. The method used here is to represent the state of the vehicle by<br />

four parameters, x, y, k, <strong>and</strong> y. The mass is used as a cost variable. The<br />

four dimensional state space is divided into small intervals in each<br />

coordinate direction. The coordinates designated by all the combinations<br />

of various intervals form a set of points in the state space. Tne vehicle<br />

starts at the initial point in the state space with some initial mass. The<br />

control <strong>and</strong> mass change that are necessary to move the vehicle from this point<br />

to the first allowable set of points in the state space are then computed.<br />

This computation corresponds to the first set of possible control decisions.<br />

Each end point of the set of possible first decisions is assigned a mass<br />

(cost) <strong>and</strong> the path that gave the cost (for the first decision the path is<br />

obvious since it must have come from the origin ).<br />

The second decision is now investigated. The required control <strong>and</strong> the<br />

correspondtig mass change required to go from the set of points at the end<br />

of the first decision to the set of all possible points at the end of the<br />

second decision must now be calculated. (The initial mass used jn this<br />

second stage calculation is the mass remaining at the end of the first stage.<br />

However, each point corresponding to the end of the second decision will<br />

have more than one possible value of mass (depending on the point from which<br />

it came). Thus, since it is desired to minimize the fuel consumed or<br />

maximize the burnout mass, the largest mass is chosen as the optimum value<br />

for that particular point. The point from which this optimum path came<br />

is then recorded.<br />

29<br />

>

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