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- - - ---------------
+
'"
R,
. "
Narrow·Band L, 1, and Pi Networks 175
+
iX'jiX,
v'
+
v,
jX 2
Figure 6.3.
Network for T-section analysis.
Then, placing (6.10) and (6.3) from Table 6.1 in (6.11) gives an expression for
the input current:
jP
1,={fie •
The current transfer phase into a resistive load is thus
1 2 = fR: e-jP
II VR; ,
where f3 is the angle by which I, lags I,.
It is now easy to verify the input impedance:
. V'
Z,=JX'+T'
]
(6.12)
(6.13)
(6.14)
Using (6.10) and (6.1) from Table 6.1 in (6.14), a little algebra shows that
Z, = R" as required. For a type-A L section, setting X, =0 in (6.5) provides
Table 6.2.
Sample Problem Data for Appendix Program 86_1°
Case R] R 2 f3 X, X 2 X,
LA 25 50 45 25 -50
LA 25 50 -45 -25 50
LB 50 25 45 -50 25
LB 50 25 -45 50 -25
T 50 50 120 86.60 -50.74 86.60
T 50 50 -120 -86.60 57.74 -86.60
T 50 50 90 50 -50 50
Pi 100 25 150 -17.45 25 -9.15
Pi 100 25 -150 17.45 -25 9.15
Pi 100 25 90 -50 50 -50
Pi 25 100 90 -50 50 -50
a Values are in ohms and lagging degrees.