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Continued Fraction Expansion<br />

It was shown in Section 3.3.2 how to find the rational polynomials for A, B,<br />

C, and D. The ABCD linear equations were given in (3.62) and (3.63),<br />

comparable to the z- and y-parameter equations above. In order to find a port<br />

immittance (impedance or admittance) as functions <strong>of</strong> ABCD when the<br />

opposite port is terminated by either a short or open circuit, it is necessary to<br />

find the z and y parameters in terms <strong>of</strong> the ABCD parameters. For example,<br />

solve for V2 in (3.63):<br />

Using this in (3.62) yields<br />

VI=II(~)+I2(D~ -B).<br />

ss<br />

(3.83)<br />

(3.84)<br />

Comparison <strong>of</strong> (3.84) with (3.77) provides z" and z12 in terms <strong>of</strong> the ABCD<br />

parameters. The coefficient <strong>of</strong> I, in (3.84) is further simplified for lossless two<br />

ports because AD- BC= I in that case. Therefore, the following identities<br />

apply for two-port networks:<br />

Z = i: [~ ~l (3.85)<br />

Y =i [_~ -U (3.86)<br />

These are valid for complex numbers or for rational functions; the latter will<br />

illustrate the last step in network synthesis. For example, (3.85) says that the<br />

open-circuit impedance parameter z" = AIC and both A(s) and C(s) were<br />

described in terms <strong>of</strong> H(s) and K(s) in (3.70). The numerator and denominator<br />

polynomials <strong>of</strong> Hand K were defined in (3.54) and (3.55). For ZII' the result is<br />

e,(s)+f,(s)<br />

z,,(s) = RI eo(s) _ fo(s) . (3.87)<br />

This is the impedance for Case I, N =4, in Figure 3.5. Note that I/Y" was<br />

relevant to N=3 but not to N=4. An example from Ternes and Mitra (1973)<br />

is given below.<br />

Example 3.14. Given the characteristic function K=S3, find z" and I/y"<br />

and the related networks. It is seen from (3.55) that f(s) = S3 and p(s) = 1. Then<br />

(3.56) is<br />

e(s)e( - s)= 1-S6= (I + s)(I- s)(1 + s+ s')(1- s+ s2). (3.88)<br />

As noted in Section 3.2.4, the roots <strong>of</strong> e(s) are the natural modes, which must<br />

be in the left-balf plane. Therefore, the transducer function according to (3.54)<br />

IS<br />

e(s)<br />

H(s)= - = (I + s)(1 + S+S2) = I + 2s+ 2s 2 +S 3 .<br />

p(s)<br />

(3.89)

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