Strona 2_redak - Instytut Agrofizyki im. Bohdana DobrzaÅskiego ...
Strona 2_redak - Instytut Agrofizyki im. Bohdana DobrzaÅskiego ...
Strona 2_redak - Instytut Agrofizyki im. Bohdana DobrzaÅskiego ...
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62<br />
A<br />
-1 5<br />
-1 0<br />
-5<br />
1 0<br />
5<br />
-5<br />
5<br />
1 0<br />
1 5<br />
2 0<br />
2 5<br />
3 0<br />
3 5<br />
40<br />
-1 0<br />
B<br />
-2 0<br />
-1 5<br />
-1 0<br />
-5<br />
1 0<br />
5<br />
-5<br />
5<br />
1 0<br />
1 5<br />
2 0<br />
2 5<br />
3 0<br />
3 5<br />
-1 0<br />
C<br />
-3 0 -2 5<br />
-1 5<br />
-1 0<br />
-5<br />
1 0<br />
5<br />
-5<br />
5<br />
1 0<br />
1 5<br />
2 0<br />
2 5<br />
Fig. 7.10. Displacement distribution across shear band ε 1 = 0.17 [64]<br />
7.2.7. Correction of change in sample cross-section area<br />
-1 0<br />
Increase in moisture content of grain results in an increase in susceptibility of<br />
grains to deformation. Grain bedding of higher moisture content requires larger<br />
displacement to attain critical state than dry grain. As a result, the surface area of<br />
cross-section of the sample perpendicular to σ 1 increases as well. This in turn leads<br />
to an increase in measurement error of the angle of internal friction because σ 1 is<br />
calculated as a ratio of vertical force and undeformed cross-section area of the<br />
sample [101]. Correction was introduced to account for change in the sample cross<br />
section area. Assuming that volume of the sample remains constant during the test:<br />
V = H (1 − ε ) 1<br />
S1<br />
= HS = const.<br />
(7.5)<br />
mean surface area S 1 of cross-section of deformed sample may be expressed as a<br />
function of strain ε 1 :<br />
S<br />
(7.6)<br />
Mean surface area obtained in this way was used to determine the corrected value<br />
of higher principal stress σ 1k :<br />
that was used for the determination of the angle of internal friction.<br />
1<br />
=<br />
S<br />
1−<br />
ε<br />
1<br />
S(<br />
σ1<br />
− σ3)<br />
σ<br />
1k<br />
= σ3<br />
+<br />
= σ3<br />
+ ( σ1<br />
− σ3)(1−<br />
ε1)<br />
,<br />
S<br />
1<br />
(7.7)