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Strona 2_redak - Instytut Agrofizyki im. Bohdana Dobrzańskiego ...

Strona 2_redak - Instytut Agrofizyki im. Bohdana Dobrzańskiego ...

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62<br />

A<br />

-1 5<br />

-1 0<br />

-5<br />

1 0<br />

5<br />

-5<br />

5<br />

1 0<br />

1 5<br />

2 0<br />

2 5<br />

3 0<br />

3 5<br />

40<br />

-1 0<br />

B<br />

-2 0<br />

-1 5<br />

-1 0<br />

-5<br />

1 0<br />

5<br />

-5<br />

5<br />

1 0<br />

1 5<br />

2 0<br />

2 5<br />

3 0<br />

3 5<br />

-1 0<br />

C<br />

-3 0 -2 5<br />

-1 5<br />

-1 0<br />

-5<br />

1 0<br />

5<br />

-5<br />

5<br />

1 0<br />

1 5<br />

2 0<br />

2 5<br />

Fig. 7.10. Displacement distribution across shear band ε 1 = 0.17 [64]<br />

7.2.7. Correction of change in sample cross-section area<br />

-1 0<br />

Increase in moisture content of grain results in an increase in susceptibility of<br />

grains to deformation. Grain bedding of higher moisture content requires larger<br />

displacement to attain critical state than dry grain. As a result, the surface area of<br />

cross-section of the sample perpendicular to σ 1 increases as well. This in turn leads<br />

to an increase in measurement error of the angle of internal friction because σ 1 is<br />

calculated as a ratio of vertical force and undeformed cross-section area of the<br />

sample [101]. Correction was introduced to account for change in the sample cross<br />

section area. Assuming that volume of the sample remains constant during the test:<br />

V = H (1 − ε ) 1<br />

S1<br />

= HS = const.<br />

(7.5)<br />

mean surface area S 1 of cross-section of deformed sample may be expressed as a<br />

function of strain ε 1 :<br />

S<br />

(7.6)<br />

Mean surface area obtained in this way was used to determine the corrected value<br />

of higher principal stress σ 1k :<br />

that was used for the determination of the angle of internal friction.<br />

1<br />

=<br />

S<br />

1−<br />

ε<br />

1<br />

S(<br />

σ1<br />

− σ3)<br />

σ<br />

1k<br />

= σ3<br />

+<br />

= σ3<br />

+ ( σ1<br />

− σ3)(1−<br />

ε1)<br />

,<br />

S<br />

1<br />

(7.7)

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