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JAEA-Data/Code 2007-004 - Welcome to Research Group for ...

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We shall discuss the following two models of neutron origin <strong>for</strong> calculating the collision rates.<br />

1) Neutron emitted from absorber grain<br />

Segev 73) proposed an expression <strong>for</strong> the self-shielding fac<strong>to</strong>r which was obtained by equating<br />

the term in the brackets of Eq.(7.3.5-13) <strong>to</strong> 1/(1 + fV Σ / V Σ )] which is the probability that a<br />

[ f f m m<br />

neutron escaping from a lump will collide in the diluent of the homogenized medium. The resultant<br />

expression is<br />

f<br />

c V Σ l f<br />

= Pe<br />

(7.3.5-15)<br />

1 − c<br />

m m<br />

V f<br />

Inserting this expression in<strong>to</strong> Eqs.(7.3.5-5), (7.3.5-6) and (7.3.5-8), we obtain<br />

l<br />

f<br />

Σ<br />

f<br />

Pe<br />

c<br />

α f ( f ) =<br />

,<br />

(7.3.5-16)<br />

1 − (1 − l Σ P ) c<br />

f<br />

f<br />

e<br />

1 − c<br />

α m ( f ) =<br />

,<br />

(7.3.5-17)<br />

1 − (1 − l P ) c<br />

f Σ f<br />

e<br />

where the index (f) of α f (f) denotes that the origin of neutron is fuel grain. It can be explained that the<br />

fraction of collision rate is measured <strong>for</strong> a neutron just having escaped from the absorber grain. That is,<br />

the probability that the neutron has the next collision with other grains is given from the expression of<br />

Eq.(7.3.5-13)<br />

Q(<br />

f , f ) − P<br />

c<br />

= 1 − Q(<br />

f , m)<br />

− (1 − P )<br />

l f Σ f Pe<br />

=<br />

1 − (1 − l Σ<br />

f<br />

2<br />

f<br />

c<br />

P ) c<br />

e<br />

e<br />

.<br />

(7.3.5-18)<br />

On the other hand, the collision with the diluent is given by Q(f, m), which can be calculated by the<br />

reciprocity relation. Dividing these quantities by the escape probability P e , we have the fractions of<br />

collision rates; α f and αm just defined by Eqs.(7.3.5-16) and (7.3.5-17). Inserting Eqs.(7.3.5-16) and<br />

(7.3.5-17) in<strong>to</strong> Eqs.(7.3.5-5) and (7.3.5-6), we obtain the same expression of f as Eq.(7.3.5-15).<br />

2) Neutron emitted from the diluent<br />

We can define the collision rate <strong>for</strong> a neutron emitted from the diluent. It is given directly by<br />

either Q(m, f) or Q(m, m). A little algebra using the reciprocity relation gives<br />

V f Σ f Pe<br />

(1 − c)<br />

α<br />

f<br />

( m)<br />

=<br />

,<br />

(7.3.5-19)<br />

V Σ 1 − (1 − l Σ P ) c<br />

m<br />

m<br />

where the index m of α f (m) denotes that the origin of neutron is the diluent.<br />

f<br />

f<br />

e<br />

269

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