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Magnetic Fields and Magnetic Diagnostics for Tokamak Plasmas

Magnetic Fields and Magnetic Diagnostics for Tokamak Plasmas

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<strong>Magnetic</strong> fields <strong>and</strong> tokamak plasmas<br />

Alan Wootton<br />

5. LOOP VOLTS, VOLTS per TURN, SURFACE VOLTAGE.<br />

Introduction<br />

The Loop Volts ε l , also called the Volts per Turn or Surface Voltage, is used in calculating the<br />

Ohmic power input to the plasma. It also allows a calculation of the plasma resistivity Ω p . ε l is<br />

also a useful measure of cleanliness: clean ohmic heated tokamaks usually have ε l ~ 1.5V.<br />

What we want to measure is the resistive voltage drop across or around a plasma. In a linear<br />

machine, this simply done by measuring the potential across the end electrodes with a resistive<br />

potential divider. A similar method can be used in a torus with a conducting vacuum vessel<br />

which has one or more insulating sections. In an all metal torus the voltage induced in a single<br />

turn pickup coil (a volts per turn loop) wound close to the plasma is used, as shown in Figure 5.1.<br />

However, the interpretation of the output signal is not trivial. Here I want to address two<br />

questions. The first is “What does a toroidal loop as shown in Figure 5.1 tell me”. The second<br />

is, “How do I measure the Ohmic power input into a plasma”.<br />

The single volts per turn loop<br />

The voltage across the toroidally wound volts per turn loop (subscript l) is given by:<br />

ε l<br />

= d dt<br />

( L l ,l<br />

I l )+ Ω l<br />

I l<br />

+<br />

∑<br />

j<br />

d<br />

dt<br />

( M l, j<br />

I j ) + d dt<br />

( M l , p<br />

I p ) 5.1<br />

Here subscript j refers to all fixed windings, such as the Ohmic heating, the vertical field, <strong>and</strong> the<br />

shaping winding. The plasma current contribution (subscript p) is brought out separately. We<br />

can arrange <strong>for</strong> the voltage of the loop to be measured with a high input resistance amplifier.<br />

Then I l ≈ 0, so that the first two terms on the RHS are zero, <strong>and</strong><br />

ε l<br />

=<br />

∑<br />

j<br />

( )<br />

d<br />

dt M l , jI j<br />

+ d dt<br />

( M l , p<br />

I p ) 5.2<br />

If this signal is time integrated, then the result is exactly the poloidal flux Ψ, because<br />

ε = d dt<br />

∫<br />

S<br />

( B• n s<br />

dS)<br />

= d dt<br />

R<br />

∫<br />

= d dt 2π B z RdR<br />

0<br />

= dΨ<br />

dt<br />

∫∫<br />

R,φ<br />

( B z<br />

RdRdφ)<br />

5.3<br />

40

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