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Quantum Field Theory I

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14 CHAPTER 1. INTRODUCTIONS<br />

• ν µ -capture 25 ν µ µ − → ν e<br />

¡<br />

e −<br />

the diagram<br />

the amplitude M fi ≈ g2 m 2 2 µ<br />

8 k 2 −MW<br />

2<br />

the cross-section σ CMS = g4 2 |⃗p e|<br />

1024π |⃗p µ|<br />

• µ-decay 26 µ − → ν µ ν e<br />

¡<br />

e −<br />

the diagram<br />

≈ g2 2 m2 µ<br />

8M 2 W<br />

m 2 µ<br />

MW<br />

4<br />

the amplitude M fi ≈ g2 2<br />

8<br />

m 2 µ<br />

k 2 −M 2 W<br />

≈ g2 2 m2 µ<br />

8M 2 W<br />

the decay rate dΓ = 1 1 g2 4 m4 µ<br />

(2π) 5 2E µ<br />

δ 4 (P<br />

64MW<br />

4 f −P i ) d3 p e d 3 p νe d 3 p νµ<br />

2E e 2E νe 2E νµ<br />

Γ = 1<br />

2 11 1<br />

(2π) 3 g 4 2 m5 µ<br />

M 4 W<br />

25 k 2 ≈ m 2 µ can be neglected when compared to M 2 W<br />

26 The diagram is the same as in the previous case, but the muon-neutrino leg is now<br />

understood to be in the final state.<br />

Since there are three particles in the final state, we cannot use the ready-made formulae<br />

for the two-particle final state. The relevant steps when going from dΓ to Γ are: the identity<br />

δ 4( P f −P i<br />

) d<br />

3 pν<br />

e<br />

2E νe<br />

d 3 p νµ<br />

2E νµ<br />

= 1 8 dΩνµ , the standard trick d 3 p e = p 2 edp edΩ e = p eE edE edΩ e and<br />

finally p e = E e for negligible m e, leading to ∫ max<br />

min EedEe = ∫ m µ/2<br />

0 E edE e = m 2 µ /8. The<br />

correct result is 8 times our result.<br />

3

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