Quantum Field Theory I
Quantum Field Theory I
Quantum Field Theory I
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14 CHAPTER 1. INTRODUCTIONS<br />
• ν µ -capture 25 ν µ µ − → ν e<br />
¡<br />
e −<br />
the diagram<br />
the amplitude M fi ≈ g2 m 2 2 µ<br />
8 k 2 −MW<br />
2<br />
the cross-section σ CMS = g4 2 |⃗p e|<br />
1024π |⃗p µ|<br />
• µ-decay 26 µ − → ν µ ν e<br />
¡<br />
e −<br />
the diagram<br />
≈ g2 2 m2 µ<br />
8M 2 W<br />
m 2 µ<br />
MW<br />
4<br />
the amplitude M fi ≈ g2 2<br />
8<br />
m 2 µ<br />
k 2 −M 2 W<br />
≈ g2 2 m2 µ<br />
8M 2 W<br />
the decay rate dΓ = 1 1 g2 4 m4 µ<br />
(2π) 5 2E µ<br />
δ 4 (P<br />
64MW<br />
4 f −P i ) d3 p e d 3 p νe d 3 p νµ<br />
2E e 2E νe 2E νµ<br />
Γ = 1<br />
2 11 1<br />
(2π) 3 g 4 2 m5 µ<br />
M 4 W<br />
25 k 2 ≈ m 2 µ can be neglected when compared to M 2 W<br />
26 The diagram is the same as in the previous case, but the muon-neutrino leg is now<br />
understood to be in the final state.<br />
Since there are three particles in the final state, we cannot use the ready-made formulae<br />
for the two-particle final state. The relevant steps when going from dΓ to Γ are: the identity<br />
δ 4( P f −P i<br />
) d<br />
3 pν<br />
e<br />
2E νe<br />
d 3 p νµ<br />
2E νµ<br />
= 1 8 dΩνµ , the standard trick d 3 p e = p 2 edp edΩ e = p eE edE edΩ e and<br />
finally p e = E e for negligible m e, leading to ∫ max<br />
min EedEe = ∫ m µ/2<br />
0 E edE e = m 2 µ /8. The<br />
correct result is 8 times our result.<br />
3