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Quantum Field Theory I

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70 CHAPTER 2. FREE SCALAR QUANTUM FIELD<br />

Representations of the canonical commutation relations without the vacuum<br />

vector are called the strange representations. The above example 22 shows not<br />

only that such representations exist, but that one can obtain (some of) them<br />

from the Fock representation by very simple algebraic manipulations.<br />

As to the Fock representation, it is always available. One just has to postulate<br />

the existence of the vacuum |0〉 and then to build the basis of the Fock<br />

space by repeated action of a + i on |0〉. Let us emphasize that even if we have<br />

proven that existence of such a state does not follow from the commutation<br />

relations in case of infinite many DOF, we are nevertheless free to postulate its<br />

existence and investigate the consequences. The very construction of the Fock<br />

space guarantees that the canonical commutation relations are fulfilled.<br />

Now to the (non-)equivalence of representations. Let us consider two representations<br />

of canonical commutation relations, i.e. two sets of operators a i ,a + i<br />

and a ′ i ,a′+ i in Hilbert spaces H and H ′ correspondingly. The representations<br />

are said to be equivalent if there is an unitary mapping H → U H ′ satisfying<br />

a ′ i = Ua iU −1 and a ′+<br />

i = Ua + i U−1 .<br />

It is quite clear that the Fock representation cannot be equivalent to a<br />

strange one. Indeed, if the representations are equivalent and the non-primed<br />

one is the Fock representation, then defining |0 ′ 〉 = U |0〉 one has ∀i a ′ i |0′ 〉 =<br />

Ua i U −1 U |0〉 = Ua i |0〉 = 0, i.e. there is a vacuum vector in the primed representation,<br />

which cannot be therefore a strange one.<br />

Perhaps less obvious is the fact that as to the canonical commutation relations,<br />

any irreducible representation (no invariant subspaces) with the vacuum<br />

vector is equivalent to the Fock representation. The proof is constructive.<br />

The considered space H ′ contains a subspace H 1 ⊂ H ′ spanned by the basis<br />

|0 ′ 〉, a ′+<br />

i |0 ′ 〉, a ′+<br />

i a ′+<br />

j |0 ′ 〉, ... One defines a linear mapping U from the subspace<br />

H 1 on the Fock space H as follows: U |0 ′ 〉 = |0〉, Ua +′<br />

i |0 ′ 〉 = a + i |0〉,<br />

Ua ′+<br />

i a ′+<br />

j |0 ′ 〉 = a + i a+ j |0〉, ... The mapping U is clearly invertible and preserves<br />

the scalar product, which implies unitarity (Wigner’s theorem). It is<br />

also straightforward that operators are transformed as Ua ′+<br />

i U −1 = a + i and<br />

Ua ′ i U−1 = a i . The only missing piece is to show that H 1 = H ′ and this follows,<br />

not surprisingly, form the irreducibility assumption 23 .<br />

22 Another instructive example (Haag 1955) is provided directly by the free field. Here the<br />

standard annihilation operators are given by a ⃗p = ϕ(⃗p,0) √ ω ⃗p /2 + iπ(⃗p,0)/ √ 2ω ⃗p , where<br />

ω ⃗p = ⃗p 2 + m 2 . But one can define another set a ′ in the same way, just with m replaced<br />

⃗p<br />

by some m ′ ≠ m. Relations between the two sets are (check it) a ′ ⃗p = c +a ⃗p + c − a + √ √<br />

−⃗p and<br />

a ′+<br />

⃗p = c −a + ⃗p +c +a −⃗p , where 2c ± = ω ⃗p ′/ω ⃗p ± ω ⃗p /ω ⃗p ′ . The commutation relations become<br />

[ ]<br />

a ′ ⃗p ,a′+ = (2π) 3 δ(⃗p− ⃗ [ ] [ ]<br />

k)(ω ⃗ ′ k ⃗p −ω ⃗p)/2ω ⃗p ′ and a ′ ⃗p ,a′ = a ′+<br />

⃗ k ⃗p ,a′+ = 0. The rescaled operators<br />

⃗ k<br />

b ⃗p = r ⃗p a ′ ⃗p and b+ ⃗p = r ⃗pa +′ where r ⃗p ⃗p 2 = 2ω′ ⃗p /(ω′ ⃗p − ω ⃗p) constitutes a representation of the<br />

canonical commutation relations.<br />

If there is a vacuum vector for a-operators, i.e. if ∃|0〉∀⃗p a ⃗p |0〉 = 0, then there is no |0 ′ 〉<br />

satisfying ∀⃗p b ⃗p |0 ′ 〉 = 0 (the proof is the same as in the example in the main text). In other<br />

words at least one of the representations under consideration is a strange one.<br />

Yet another example is provided by an extremely simple prescription b ⃗p = a ⃗p +α(⃗p), where<br />

α(⃗p) is a complex-valued function. For ∫ |α(⃗p)| 2 = ∞ this representation is a strange one (the<br />

proof is left to the reader as an exercise)<br />

23 As always with this types of proofs, if one is not quite explicit about definition domains<br />

of operators, the ”proof” is a hint at best. For the real, but still not complicated, proof along<br />

the described lines see Berezin, Metod vtornicnovo kvantovania, p.24.

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