Balancing of a Water and Air System (PDF
Balancing of a Water and Air System (PDF
Balancing of a Water and Air System (PDF
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Example 14: Fine the tons <strong>of</strong> a condenser that has a 8” SCH 40 with a pressure <strong>of</strong><br />
23.347psig <strong>and</strong> a total pressure <strong>of</strong> 23.352 psig <strong>and</strong> a entering water <strong>of</strong> 85º <strong>and</strong> leaving<br />
water <strong>of</strong> 93º.<br />
Solution<br />
• Total pressure – Pressure = VP<br />
• FPM = 1040 X √ VP<br />
• GPM = FPM X Gallons per foot<br />
• Ton = GPM X 60 X 8.337 X ∆ Temperature <strong>of</strong> the water<br />
• 23.352 psig – 23.347 = 0.005 VP<br />
• 1040 X √ 0.005 = 73.54 FPM<br />
• 73.54 X 2.6 gallons per foot = 191.20 GPM<br />
• 191.20 X 60 X 8.337 X 8 = 765,136.5 btuh<br />
• 765,136.5 / 15,000 = 51.01 tons<br />
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