17.11.2012 Views

Balancing of a Water and Air System (PDF

Balancing of a Water and Air System (PDF

Balancing of a Water and Air System (PDF

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

47<br />

Wet bulb temperature_____________°F<br />

Dry bulb temperature _____________°F<br />

(3) On Table 8 A&B find, the Foot³ <strong>of</strong> the leaving air <strong>of</strong> the evaporate.<br />

(4) Divide the Foot³ by one pound <strong>of</strong> air; this is the air density <strong>of</strong> the air. <strong>Air</strong><br />

density_____________________ or use Table 9B or 9C for air density<br />

(5) Find the CFM <strong>of</strong> the system<br />

CFM_______________________<br />

(6) Using the Wet bulb find the enthalpy <strong>of</strong> the air that is going in <strong>and</strong> out <strong>of</strong> the<br />

evaporator Tables 11<br />

Enthalpy air in ____________ EP<br />

Enthalpy air out ____________ EP<br />

Difference in EP _____________∆EP<br />

(7) Run the formula; <strong>Air</strong> Density X 60 X CFM X ∆EP = BTUH<br />

Example 6: Find the total heat that <strong>of</strong> a evaporator fan coil is absorbing from air with 4050<br />

cfm <strong>and</strong> entering air <strong>of</strong> 76º dry bulb <strong>and</strong> 64ºwet bulb, leaving air <strong>of</strong> 58ºdry bulb <strong>and</strong> 54ºwet<br />

bulb.<br />

Solution<br />

76º dry bulb <strong>and</strong> 66ºwet bulb has a enthalpy <strong>of</strong> 30.75<br />

58ºdry bulb <strong>and</strong> 54ºwet bulb has a enthalpy <strong>of</strong> 22.60 <strong>and</strong> a air density <strong>of</strong> 0.0757<br />

<strong>Air</strong> density X 60 X cfm X ∆ enthalpy = Btuh<br />

0.0757 X 60 X 4050 X 8.15 = 149,920 Btuh<br />

Example 7: Find the airflow <strong>and</strong> velocity fpm <strong>of</strong> a fan coil with a duct <strong>of</strong> 48 X 36 <strong>and</strong> a 75<br />

gpm with an entering water <strong>of</strong> 45º <strong>and</strong> a leaving water 56º. On the airside, the entering air<br />

temperature is 78º dry bulb <strong>and</strong> 65º wet bulb with a leaving air temperature <strong>of</strong> 60º dry<br />

bulb <strong>and</strong> 56º wet bulb.<br />

Solution<br />

Btuh = gpm X 60 X 8.337 X ∆ Temperature water<br />

Cfm = Btuh / (air density X 60 X ∆ enthalpy (h1-h2)<br />

47

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!