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Page 2 Lecture Notes in Computer Science 2865 Edited by G. Goos ...

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138 J. Deng, Y.S. Han, and Z.J. HaasThroughput Comparison of MAC−1 and MAC−2R, S 2R/S 110.90.80.70.60.50.40.30.20.1L d=1024L d=2048L d=409600 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5Ratio of control channel over entire channel, rFig. 6. Throughput comparisons between MAC-1 and MAC-2Rat 0.78 4 . When the MAC-2R scheme is optimized accord<strong>in</strong>g to the expectedvalue of the contention resolution periods, i.e., sett<strong>in</strong>g r to r ∗ , we conclude thatthe throughput degradation of the MAC-2R scheme over the MAC-1 scheme canbe as high as 22%.5 ConclusionsIn wireless communication networks, the Medium Access Control (MAC) schemecan significantly affect the performance of the network system. To improve thethroughput performance of MAC schemes on random access channels, some researchersproposed to split the s<strong>in</strong>gle shared channel <strong>in</strong>to two subchannels: a controlsubchannel and a data subchannel. Control packets are sent on the controlsubchannel, while the data subchannel is used solely to transmit data packets.Therefore, separation of control packet transmission and data packet transmissionis achieved.Some previous publications <strong>in</strong> the literature claimed that the split-channelMAC scheme may achieve the same or better throughput as the correspond<strong>in</strong>gs<strong>in</strong>gle-channel MAC scheme does. However, as we show <strong>in</strong> this paper, theseoptimistic results were derived <strong>by</strong> consider<strong>in</strong>g only the expected value of the contentionresolution periods, without tak<strong>in</strong>g <strong>in</strong>to the account the random distributionof these periods. When the randomness of the contention resolution periodsis considered, the split-channel schemes are <strong>in</strong>ferior to the s<strong>in</strong>gle-channel scheme<strong>in</strong> fully-connected networks and for the scenarios that we have studied here. Accord<strong>in</strong>gto our analysis, this result holds even if the split-channel schemes areoptimized with respect to the ratio of the bandwidth of the control subchannelto the bandwidth of the entire channel.[( ) ]∣4In fact, when r = r ∗ = w+2w+2+k , S 12R/S 1 = 1/1−r + w2 k ∣∣r=rkr w+2+k=∗( )1/ 1+ w2w+2. S<strong>in</strong>ce δ = w + 2 and it is not related to k, w 2 is not related tok accord<strong>in</strong>g to (6). Therefore, the ratio S 2R /S 1 is not related to k.

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