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Page 2 Lecture Notes in Computer Science 2865 Edited by G. Goos ...

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182 G. Cal<strong>in</strong>escuRyvxFig. 3. The unnamed nodes <strong>in</strong> the figure can jo<strong>in</strong> the rigid piece started <strong>by</strong> v, x,and y. In the system of coord<strong>in</strong>ates used, v is the orig<strong>in</strong>, x has second coord<strong>in</strong>ate0, and y has the second coord<strong>in</strong>ate positive. Notice that every node <strong>in</strong> the sectorof the disk R = R i can jo<strong>in</strong> the rigid piece and that R covers at least 1/6 oftheunit disk centered at vx’y’xjxivzyjyix"y"Fig. 4. There could be at most three sectors R k which conta<strong>in</strong> the po<strong>in</strong>t z: thefirst given <strong>by</strong> x i and y i (which are on opposite sides of the l<strong>in</strong>e vz) and thentwo sectors given <strong>by</strong> x ′ and y ′ (both above the l<strong>in</strong>e vz) and <strong>by</strong> x” and y” (bothunder the l<strong>in</strong>e vz). As shown <strong>in</strong> proof of Theorem 2, a fourth sector such as theone given <strong>by</strong> x j and y j cannot existsconsist<strong>in</strong>g of the po<strong>in</strong>ts z with angles ̂ zvx i at most π/3. Figure 3 aga<strong>in</strong> provides<strong>in</strong>tuition.We claim that any po<strong>in</strong>t z belongs to at most three sectors R i ,1≤ i ≤ k.See Figure 4 for <strong>in</strong>tuition. Indeed, if there are i

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