10.12.2012 Views

String Theory and M-Theory

String Theory and M-Theory

String Theory and M-Theory

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

of Eq. (11.46) is<br />

where<br />

11.3 Black holes in string theory 575<br />

ds 2 = −λ −1/2 dt 2 + λ 1/2 dr 2 + r 2 dΩ 2 2 , (11.77)<br />

λ =<br />

4 <br />

1 + ri<br />

<br />

. (11.78)<br />

r<br />

i=1<br />

This reduces to Eq. (11.30) when all four ri are equal. We can read off the<br />

mass of the black hole from the large distance behavior of gtt using Eqs (11.7)<br />

<strong>and</strong> (11.8). The result is<br />

M =<br />

4<br />

i=1<br />

Mi with Mi = ri<br />

The area of the horizon, which is located at r = 0, is<br />

. (11.79)<br />

4G4<br />

A = 4π √ r1r2r3r4. (11.80)<br />

Putting these facts together, the resulting entropy is<br />

S = A<br />

4G4<br />

<br />

= 16πG4 M1M2M3M4. (11.81)<br />

Type IIA brane construction<br />

It still remains to relate the four masses to four electric (or magnetic)<br />

charges. This requires some sort of brane construction involving four types<br />

of branes or excitations. To be specific, let us consider the type IIA theory<br />

compactified on a six torus that is a product of six circles with coordinates<br />

y 1 , . . . , y 6 <strong>and</strong> radii R1, . . . , R6. A brane configuration that preserves 1/8 of<br />

the N = 8 supersymmetry, <strong>and</strong> therefore is suitable, is the following: Q1<br />

D2-branes wrapped on the y 1 <strong>and</strong> y 6 circles, Q2 D6-branes wrapped on all<br />

six circles, Q3 NS5-branes wrapped on the first five circles, <strong>and</strong> Q4 units of<br />

Kaluza–Klein momentum on the first circle. The masses that correspond to<br />

these types of excitations are<br />

M1 = (2πR1)(2πR6)TD2Q1 = 1<br />

gsℓ3 (R1R6)Q1,<br />

s<br />

M2 = (2πR1) · · · (2πR6)TD6Q2 = 1<br />

gsℓ7 (R1 · · · R6)Q2,<br />

s<br />

M3 = (2πR1) · · · (2πR5)TNS5Q3 = 1<br />

g2 s ℓ6 (R1 · · · R5)Q3,<br />

s<br />

M4 = 1<br />

R1 Q4.<br />

(11.82)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!