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String Theory and M-Theory

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580 Black holes in string theory<br />

(2π) 4 V , <strong>and</strong> Q1 F1-branes wrapping the y 1 circle, which has radius R. This<br />

leads to the masses<br />

M1 = Q0<br />

, M2 =<br />

gsℓs<br />

Q4<br />

(2π) 4 gsℓ 5 s<br />

(2π) 4 V, M3 = Q1<br />

2πℓ2 2πR.<br />

s<br />

Inserting this into the expression for the entropy Eq. (11.54) gives<br />

S = A<br />

4G5<br />

= 2πgsℓ4 <br />

s √ M1M2M3 = 2π<br />

RV<br />

Q0Q4Q1.<br />

Comparison of this formula with Eq. (11.55) shows that the D0-D4-F1 system<br />

gives the same entropy for Q0 = Q1, Q4 = Q5 <strong>and</strong> Q1 = n, which is<br />

what we wanted to show.<br />

Note that the various dualities that relate the different brane descriptions<br />

of the black hole do not change the five-dimensional metric except by an<br />

overall constant factor. Such a factor has no bearing on the computation of<br />

the entropy, which is dimensionless.<br />

✷<br />

EXERCISE 11.7<br />

Compute the area of the horizon of the rotating black hole described in<br />

Section 11.3 <strong>and</strong> deduce its entropy.<br />

SOLUTION<br />

In the near-horizon limit r ≈ 0 <strong>and</strong> constant t the metric Eq. (11.74) reduces<br />

to<br />

ds 2 = R 2 dΩ 2 3 − (a/R 2 ) 2 (cos 2 θdψ − sin 2 θdφ) 2<br />

= R 2 dθ 2 + R 2 (cos θ sin θ) 2 (dφ + dψ) 2 + (R 2 − (a/R 2 ) 2 )(cos 2 θdψ − sin 2 θdφ) 2 ,<br />

where<br />

R 2 = (r1r2r3) 2/3 .<br />

The easiest way to compute the area of the horizon described by this metric<br />

is to define the orthonormal one-forms<br />

e1 = Rdθ,<br />

e2 = R cos θ sin θ(dφ + dψ),<br />

e3 = R 2 − (a/R 2 ) 2 (cos 2 θdψ − sin 2 θdφ).

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