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String Theory and M-Theory

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98 Conformal field theory <strong>and</strong> string interactions<br />

this takes the form<br />

I =<br />

+1/2<br />

−1/2<br />

∞<br />

dx √<br />

1−x2 +1/2<br />

dy<br />

=<br />

y2 −1/2<br />

dx<br />

√ 1 − x 2<br />

= π<br />

3 ,<br />

where we have set τ = x + iy. ✷<br />

3.6 The linear-dilaton vacuum <strong>and</strong> noncritical strings<br />

An interesting example of a nontrivial background that preserves conformal<br />

symmetry is one in which the dilaton field depends linearly on the spatial<br />

coordinates. Letting y denote the direction along which it varies <strong>and</strong> x µ the<br />

other D − 1 space-time coordinates, the linear dilaton background is<br />

Φ(X µ , Y ) = kY (z, ¯z), (3.132)<br />

where k is a constant. After fixing the conformal gauge, the dilaton term<br />

no longer contributes to the world-sheet action, which remains independent<br />

of k, but it does contribute to the energy–momentum tensor.<br />

The energy–momentum tensor for the linear-dilaton background is derived<br />

by varying the action with respect to the world-sheet metric before fixing<br />

the conformal gauge. The result is<br />

T (z) = −2(∂X µ ∂Xµ + ∂Y ∂Y ) + k∂ 2 Y. (3.133)<br />

This expression gives a T T OPE that still has the correct structure to define<br />

a CFT. One peculiarity is that the OPE of T with Y has an extra term<br />

(proportional to k), which implies that ∂Y does not satisfy the definition of<br />

a conformal field.<br />

Calling D the total space-time dimension (including Y ), the central charge<br />

determined by the T T OPE turns out to be<br />

c = ˜c = D + 3k 2 . (3.134)<br />

Thus, the required value c = 26 can be achieved for D < 26 by choosing<br />

<br />

26 − D<br />

k = . (3.135)<br />

3<br />

Of course, there is Lorentz invariance in only D − 1 dimensions, since the<br />

Y direction is special. Theories with k = 0 are called noncritical string<br />

theories.<br />

The extra term in T contributes to L0, <strong>and</strong> hence to the equation of motion<br />

for the free tachyon field t(x µ , y). For simplicity, let us consider solutions

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