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String Theory and M-Theory

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Homework Problems 57<br />

PROBLEM 2.11<br />

The open-string states at the N = 2 level were shown in Section 2.5 to form<br />

a certain representation of SO(25). What does this result imply for the<br />

spectrum of the closed bosonic string at the NL = NR = 2 level?<br />

PROBLEM 2.12<br />

Construct the spectrum of open <strong>and</strong> closed strings in light-cone gauge for<br />

level N = 3. How many states are there in each case? Without actually<br />

doing it (unless you want to), describe a strategy for assembling these states<br />

into irreducible SO(25) multiplets.<br />

PROBLEM 2.13<br />

We expect the central extension of the Virasoro algebra to be of the form<br />

[Lm, Ln] = (m − n)Lm+n + A(m)δm+n,0,<br />

because normal-ordering ambiguities only arise for m + n = 0.<br />

(i) Show that if A(1) = 0 it is possible to change the definition of L0, by<br />

adding a constant, so that A(1) = 0.<br />

(ii) For A(1) = 0 show that the generators L0 <strong>and</strong> L±1 form a closed<br />

subalgebra.<br />

PROBLEM 2.14<br />

Derive an equation for the coefficients A(m) defined in the previous problem<br />

that follows from the Jacobi identity<br />

[[Lm, Ln], Lp] + [[Lp, Lm], Ln] + [[Ln, Lp], Lm] = 0.<br />

Assuming A(1) = 0, prove that A(m) = (m 3 − m)A(2)/6 is the unique<br />

solution, <strong>and</strong> hence that the central charge is c = 2A(2).<br />

PROBLEM 2.15<br />

Verify that the Virasoro generators in Eq. (2.91) satisfy the Virasoro algebra.<br />

It is difficult to verify the central-charge term directly from the commutator.<br />

Therefore, a good strategy is to verify that A(1) <strong>and</strong> A(2) have the correct<br />

values. These can be determined by computing the ground-state matrix<br />

element of Eq. (2.93) for the cases m = −n = 1 <strong>and</strong> m = −n = 2.

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