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String Theory and M-Theory

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46 The bosonic string<br />

Determination of the space-time dimension<br />

The number of zero-norm spurious states increases dramatically if, in addition<br />

to a = 1, the space-time dimension is chosen appropriately. To see this,<br />

let us construct zero-norm spurious states of the form<br />

|ψ〉 = L−2 + γL 2 <br />

−1 |χ〉. (2.116)<br />

This has zero norm for a certain γ, which is determined below. Here |ψ〉 is<br />

spurious if |χ〉 is a state that satisfies<br />

(L0 + 1)|χ〉 = Lm|χ〉 = 0 for m = 1, 2, . . . (2.117)<br />

Now impose the condition that |ψ〉 is a physical state, that is, L1|ψ〉 = 0 <strong>and</strong><br />

L2|ψ〉 = 0, since the rest of the constraints Lm|ψ〉 = 0 for m ≥ 3 are then<br />

also satisfied as a consequence of the Virasoro algebra. Let us first evaluate<br />

the condition L1|ψ〉 = 0 using the relation<br />

This leads to<br />

<br />

L1, L−2 + γL 2 <br />

−1 = 3L−1 + 2γL0L−1 + 2γL−1L0<br />

= (3 − 2γ)L−1 + 4γL0L−1. (2.118)<br />

<br />

L1|ψ〉 = L1 L−2 + γL 2 <br />

−1 |χ〉 = [(3 − 2γ) L−1 + 4γL0L−1] |χ〉. (2.119)<br />

The first term vanishes for γ = 3/2 while the second one vanishes in general,<br />

because<br />

L0L−1|χ〉 = L−1(L0 + 1)|χ〉 = 0. (2.120)<br />

Therefore, the result of evaluating the L1|ψ〉 = 0 constraint is γ = 3/2. Let<br />

us next consider the L2|ψ〉 = 0 condition. Using<br />

<br />

L2, L−2 + 3<br />

2 L2 <br />

−1 = 13L0 + 9L−1L1 + D<br />

(2.121)<br />

2<br />

gives<br />

L2|ψ〉 = L2<br />

<br />

L−2 + 3<br />

2 L2 −1<br />

<br />

|χ〉 =<br />

<br />

−13 + D<br />

<br />

|χ〉. (2.122)<br />

2<br />

Thus the space-time dimension D = 26 gives additional zero-norm spurious<br />

states.

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