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String Theory and M-Theory

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598 Black holes in string theory<br />

where G (4)<br />

µν is the four-dimensional metric, λ is a scalar <strong>and</strong> Aµ is a U(1)<br />

gauge field. The four-dimensional metric satisfies the two-center attractor<br />

equations.<br />

EXERCISES<br />

EXERCISE 11.10<br />

Deduce Eq. (11.118) by projecting both sides of Eq. (11.120) on e −iα+K/2 Ω.<br />

SOLUTION<br />

Equation (11.120) is equivalent to<br />

d<br />

dτ<br />

<br />

−U<br />

e e −iα+K/2 Ω − e iα+K/2 Ω<br />

<br />

∼ −iΓ.<br />

Taking the wedge product with e−iα+K/2Ω, only the second term on the left<br />

contributes since Ω ∧ Ω = Ω ∧ d<br />

dτ Ω = 0. Thus<br />

− d −U<br />

e<br />

dτ<br />

e K Ω ∧ Ω − e −U e −iα+K/2 Ω ∧ d<br />

<br />

e<br />

dτ<br />

iα+K/2 <br />

Ω<br />

∼ −ie −iα+K/2 Ω ∧ Γ.<br />

The imaginary part of this equation is now integrated over the manifold. A<br />

useful identity that implies that the integral of the second term is real is<br />

<br />

e iα+K/2 Ω ∧ d<br />

<br />

e<br />

dτ<br />

−iα+K/2 <br />

Ω = e −iα+K/2 Ω ∧ d<br />

<br />

e<br />

dτ<br />

iα+K/2 <br />

Ω ,<br />

which is derived by differentiating Eq. (11.110) written in the form<br />

<br />

e −iα+K/2 <br />

Ω ∧ e iα+K/2 <br />

Ω = −i.<br />

In this way, one obtains<br />

i d −U<br />

e<br />

dτ<br />

e K<br />

<br />

Ω ∧ Ω = − 1<br />

2 eK/2<br />

<br />

e −iα iα<br />

Ω + e Ω ∧ Γ.<br />

Using Eq. (11.110) to simplify the left-h<strong>and</strong> side <strong>and</strong> Eq. (11.114) to simplify<br />

the right-h<strong>and</strong> side, one obtains<br />

d −U<br />

e<br />

dτ<br />

= |Z|,

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