الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

Capacitors and capacitance
Example 6.5
Three capacitors of 8µF, 10µF and 14µF are connected to a battery of
12V. How much energy does the battery supply if the capacitors are
connected (a) in series and (b) in parallel?
Solution
(a) For series combination
1
C
1
=
C
1
1
+
C
2
1
+
C
3
1
C
=
1
8
+
1
10
+
1
14
This gives
C = 3.37 µF
Then the energy U is
1 U = CV
2
2
U = 1/2 (3.37×10 -6 ) (12) 2 = 2.43×10 -4 J
(b) For parallel combination
C = C +
1
+ C2
C3
C= 8+10+14=32µF
The energy U is
U = 1/2 (32×10 -6 ) (12) 2 = 2.3×10 -3 J
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