الفيزياء العامة الجزء الثاني#موقع الفيزياء.كوم

Capacitors and capacitance
Example 6.9
Four capacitors are connected as shown in Figure 6.13. (a) Find the
equivalent capacitance between points a and b. (b) Calculate the charge
on each capacitor if V ab =15V.
15uF
3uF
a
Ac
24uF
Ab
6uF
Figure 6.13
Solution
(a) We simplify the circuit as shown in the figure from (a) to (c).
2.5uF
a
Ac
24uF
Ab
2.5uF 24uF
aa Ac Ab
aa
5.96uF
Ab
6uF
(a) (b) (c)
Firs the 15µF and 3µF in series are equivalent to
1
(1/15)
+ (1/ 3)
= 2.5µF
Next 2.5µF combines in parallel with 6µF, creating an equivalent
capacitance of 8.5µF.
The 8.5µF and 20µF are in series, equivalent to
1
(1/ 8.5) + (1/ 20)
= 5.96µF
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